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Is x<y<z? 1)|x-1|<y<z+1 2)|x+1|<y<z-1

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Is x<y<z? 1)|x-1|<y<z+1 2)|x+1|<y<z-1 [#permalink]

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New post 19 Feb 2017, 15:46
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A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

51% (01:15) correct 49% (01:52) wrong based on 35 sessions

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Is \(x<y<z\) ?

1) \(|x-1|<y<z+1\)
2) \(|x+1|<y<z-1\)

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Re: Is x<y<z? 1)|x-1|<y<z+1 2)|x+1|<y<z-1 [#permalink]

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New post 20 Feb 2017, 03:00
Is \(x<y<z\) ?

1) \(|x-1|<y<z+1\)
y<z+1, so y may be less than z... Example y is 3 and z is 4..
y may not be less than z, ... Example y is 3 and z is 2.5..
Insufficient

2) \(|x+1|<y<z-1\)
If y<z-1, y will surely be less than z..
Also if |x+1|<y, y is POSITIVE and will always be >x..
Ans is YES
Sufficient

B
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Re: Is x<y<z? 1)|x-1|<y<z+1 2)|x+1|<y<z-1   [#permalink] 20 Feb 2017, 03:00
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