This is a Yes/No type of question which involves plugging in values.
Constraints: None. x, y can be any type of number, integers or fractions (negative or positive)
Statement 1: \(x > \frac{1}{y}\)
Most would think that cross multiplying, we get xy is > 1, and therefore it answers our question. This can only be possible if both x and y are positive.
Lets put in some values and see.
Both positive: x = 2, y = 2; \(2 > \frac{1}{2}\) and xy = 4 which is > 1. Therefore YES
Both negative: x = -0.2, y = -2; \(-0.2 > \frac{1}{-2}\) and xy = 0.4 which is < 1. Therefore NO
Statement 1 is Insufficient. Answer options could be B, C or E
Statement 2: y is positive
If x is positive, then xy will be > 0, but can be greater than 1, equal to 1 or less than 1.
Let us check this with some values
x = 0.2, y = 4, xy = 0.8 which is < 1
x = 0.5, y = 2, xy = 1
x = 2, y = 4, xy = 8 which is > 1
If x is negative, then xy will definitely be less than 0.
Statement 2 is Also Insufficient. Answer Options could be C or E
Combining Both Statements: \frac{1}{y}[/m] and y is positive
This, as discussed in statement 1, cross multiplying we get xy > 1
Therefore Both Statements together are sufficient.
Option C
Arun Kumar