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Bunuel
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Let the escalator be 120 meters in length [LCM of 60 and 24]

Speed of Clea when the escalator is not operating: C = \(\frac{120 }{60}\) = 2

Speed of both Clea and the escalator when it is operating: C + E = \(\frac{120 }{24}\) = 5

Therefore, only escalator's speed: E = 5 - 2 = 3

Time taken only by escalator: \(\frac{120 }{ 3}\) = 40

Answer B
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what if we use working together method to solve. let's say 1/60 + 1/x = 1/24, x=40 sec
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Deconstructing the Question (Ratio Method)
The distance (escalator length) is constant.
Therefore, Time and Speed are inversely proportional. This allows us to solve the problem using simple ratios without assuming a specific distance.

  • Time (Walking) \(T_w\): 60s
  • Time (Combined) \(T_{comb}\): 24s

Step 1: Establish the Time Ratio
Compare the time taken walking alone vs. walking with the escalator moving.
\(T_w : T_{comb} = 60 : 24\)
Simplify by dividing by 12:
\(T_w : T_{comb} = 5 : 2\)

Step 2: Invert to get Speed Ratio
Since Speed is inversely proportional to Time, we flip the ratio values.
\(S_w : S_{comb} = 2 : 5\)

This tells us:
  • Walking Speed contributes 2 units.
  • Combined Speed contributes 5 units.

Step 3: Isolate the Escalator's Speed
The Combined Speed is simply Walking Speed + Escalator Speed.
\(S_{esc} = S_{comb} - S_w\)
\(S_{esc} = 5 - 2 = 3 \text{ units}\)

Step 4: Calculate the Time for the Escalator
We know that a speed of 2 units takes 60 seconds.
We need to find the time for a speed of 3 units.

Using the inverse proportion (\(Speed \times Time = Constant\)):
\(2 \times 60 = 3 \times t_{esc}\)
\(120 = 3 \times t_{esc}\)
\(t_{esc} = 40 \text{ seconds}\)

Answer: B
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