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Jack has 5 cats and 1 dog. If the dog`s weight is 3 times the average

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Jack has 5 cats and 1 dog. If the dog`s weight is 3 times the average  [#permalink]

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New post 23 Aug 2018, 04:25
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A
B
C
D
E

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Jack has 5 cats and 1 dog. If the dog`s weight is 3 times the average  [#permalink]

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New post Updated on: 23 Aug 2018, 06:14
Bunuel wrote:
Jack has 5 cats and 1 dog. If the dog's weight is 3 times the average (arithmetic mean) weight of the cats, then the dog's weight is what fraction of the total weight of all 6 animals?


A. 1/4
B. 1/3
C. 3/8
D. 3/7
E. 3/5



let the sum of weight of all the cats be c
and weight of a dog be d
d=3(c/5)
total weight of all animals = c+d = c+3c/5 = 8c/5
ratio = (3c/5)/(8c/5) = 3/8

Originally posted by CounterSniper on 23 Aug 2018, 04:36.
Last edited by CounterSniper on 23 Aug 2018, 06:14, edited 1 time in total.
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Re: Jack has 5 cats and 1 dog. If the dog`s weight is 3 times the average  [#permalink]

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New post 23 Aug 2018, 04:49
Bunuel wrote:
Jack has 5 cats and 1 dog. If the dog's weight is 3 times the average (arithmetic mean) weight of the cats, then the dog's weight is what fraction of the total weight of all 6 animals?


A. 1/4
B. 1/3
C. 3/8
D. 3/7
E. 3/5


Let the average weight of the cats be x. The weight of the 5 cats is 5*Average = 5x

Since the dog's weight is 3 times the average of the cats, the weight of the dog is 3x.

Therefore, the weight of the dog is \(\frac{3x}{3x+5x} = \frac{3x}{8x} = \frac{3}{8}\)th(Option C) the weight of all 6 animals.
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Re: Jack has 5 cats and 1 dog. If the dog`s weight is 3 times the average  [#permalink]

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New post 23 Aug 2018, 06:00
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Re: Jack has 5 cats and 1 dog. If the dog`s weight is 3 times the average  [#permalink]

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New post 23 Aug 2018, 06:39
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Bunuel wrote:
Jack has 5 cats and 1 dog. If the dog's weight is 3 times the average (arithmetic mean) weight of the cats, then the dog's weight is what fraction of the total weight of all 6 animals?


A. 1/4
B. 1/3
C. 3/8
D. 3/7
E. 3/5

\(5c + 3c = 8c =\) Total weight of 5 Cats and 1 Dog

So, the dog's weight is \(\frac{3c}{8c} = \frac{3}{8}\) of the total weight of the \(6\) animals , Answer must be (C)
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Jack has 5 cats and 1 dog. If the dog`s weight is 3 times the average  [#permalink]

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New post 23 Aug 2018, 15:49
Bunuel wrote:
Jack has 5 cats and 1 dog. If the dog's weight is 3 times the average (arithmetic mean) weight of the cats, then the dog's weight is what fraction of the total weight of all 6 animals?


A. 1/4
B. 1/3
C. 3/8
D. 3/7
E. 3/5


Average weight of cats = x

the total weight of 5 cats = 5x

Dog's weight = 3x.

Total weight of 6 animals = 5x + 3x = 8x.

Required Fraction : \(\frac{3x}{8x}\)=\(\frac{3}{8}\)

The best answer is C.
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Re: Jack has 5 cats and 1 dog. If the dog`s weight is 3 times the average  [#permalink]

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New post 26 Aug 2018, 19:24
Bunuel wrote:
Jack has 5 cats and 1 dog. If the dog's weight is 3 times the average (arithmetic mean) weight of the cats, then the dog's weight is what fraction of the total weight of all 6 animals?


A. 1/4
B. 1/3
C. 3/8
D. 3/7
E. 3/5


We can let the average weight of the cats = x. Thus, the dog weighs 3x, and the total weight of the 5 cats is 5x. So the dog’s weight is 3x/(3x + 5x) = 3x/8x = 3/8 of the total weight of the 6 animals.

Answer: C
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Re: Jack has 5 cats and 1 dog. If the dog`s weight is 3 times the average  [#permalink]

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New post 03 Jul 2019, 02:19
Test numbers:

Cat: 1 (kg) >> Dog: 1*3=3 (kg)

5 cats: 5 (kg) + 1 dog: 3 (kg) = 8 (kg)

Part/Whole >> Dog/Total >> 3/8

Ans C
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Re: Jack has 5 cats and 1 dog. If the dog`s weight is 3 times the average   [#permalink] 03 Jul 2019, 02:19
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