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23 Aug 2018, 04:25
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
83% (01:36) correct
17%
(01:58)
wrong
based on 296
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Jack has 5 cats and 1 dog. If the dog's weight is 3 times the average (arithmetic mean) weight of the cats, then the dog's weight is what fraction of the total weight of all 6 animals?
A. 1/4
B. 1/3
C. 3/8
D. 3/7
E. 3/5
A. 1/4
B. 1/3
C. 3/8
D. 3/7
E. 3/5
Updated on: 23 Aug 2018, 06:14
Originally posted by CounterSniper on 23 Aug 2018, 04:36.
Last edited by CounterSniper on 23 Aug 2018, 06:14, edited 1 time in total.
Last edited by CounterSniper on 23 Aug 2018, 06:14, edited 1 time in total.
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Bunuel
let the sum of weight of all the cats be c
and weight of a dog be d
d=3(c/5)
total weight of all animals = c+d = c+3c/5 = 8c/5
ratio = (3c/5)/(8c/5) = 3/8
23 Aug 2018, 04:49
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Bunuel
Let the average weight of the cats be x. The weight of the 5 cats is 5*Average = 5x
Since the dog's weight is 3 times the average of the cats, the weight of the dog is 3x.
Therefore, the weight of the dog is \(\frac{3x}{3x+5x} = \frac{3x}{8x} = \frac{3}{8}\)th(Option C) the weight of all 6 animals.
