Let his base salary = s and his commission = c
January:\( s + 30c = 4000\)
February: \(s + 50c = 6000\)
Subtracting January's sum from February's sum yields: \(20c = 2000\)
\(c = 100\) and plugging that back into either will give \(s = 1000\)
March: \(s + 70c = 7200\)
As there is a drop of x% in commission after the 50th item sold, we can subtract February's sum from March's sum to solve for x.
Subtracting February's sum from March's sum: \(20c = 1200\)
\(c = 60\)
As the commission went down from 100 to 60 per item sold, there is a 40% drop. \(x = 40\) Which means that the commission for after 100 items sold will be: \(60 * 0.6 = 36\)
April: Taking March's total, which covers 70 items sold, then adding 30*60 to cover up until the 100th item sold and then finally adding 20*36 to cover the final 20 items sold over 100 will give us his remuneration for April.
\(7200 + (30*60) + (20*36)\)
\(= 7200 + 1800 + 720\)
\(= 9720\)
Answer D