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Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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08 Nov 2015, 09:35
Question Stats:
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Jamboree and GMAT Club Contest Starts QUESTION #5:A box contains 100 balls, numbered from 1 to 100. If 3 balls are selected at random and with replacement from the box. If the 3 numbers on the balls selected contain two odd and one even. What is the probability that the first ball picked up is odd numbered? (A) 0 (B) 1/3 (C) 1/2 (D) 2/3 (E) 1 Check conditions below: For the following two weekends we'll be publishing 4 FRESH math questions and 4 FRESH verbal questions per weekend. To participate, you will have to reply with your best answer/solution to the new questions that will be posted on Saturday and Sunday at 9 AM Pacific. Then a week later, respective forum moderators will be selecting 2 winners who provided most correct answers to the questions, along with best solutions. Those winners will get 6months access to GMAT Club Tests. PLUS! Based on the answers and solutions for all the questions published during the project ONE user will be awarded with ONE Grand prize. He/She can opt for one of the following as a Grand Prize. It will be a choice for the winner:  GMAT Online Comprehensive ( If the student wants an online GMAT preparation course)  GMAT Classroom Program ( Only if he/she has a Jamboree center nearby and is willing to join the classroom program) Bookmark this post to come back to this discussion for the question links  there will be 2 on Saturday and 2 on Sunday! There is only one Grand prize and student can choose out of the above mentioned too options as per the conditions mentioned in blue font.All announcements and winnings are final and no whining GMAT Club reserves the rights to modify the terms of this offer at any time. NOTE: Test Prep Experts and Tutors are asked not to participate. We would like to have the members maximize their learning and problem solving process.
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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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09 Nov 2015, 23:09
We are given that, out of the three balls selected 2 are odd and 1 is even. We can have the following arrangements: OOE, OEO, EOO P(1st ball is odd numbered) = 2/3
Answer: D




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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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08 Nov 2015, 09:57
The question seeks, what is the prob that the first ball picked is odd...?
When we start, total no of odd balls = 50 When we start, total no of ball = 100.
Required probability is = Ways of selecting 1 odd ball / Ways of selecting one ball = 50 C 1 / 100 C 1 = 50/100 = 1/2.
The answer is C.



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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08 Nov 2015, 11:52
Hi,
The probability of any number to be picked is independent of whether it is an odd or an even.
So P(O) = 1



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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08 Nov 2015, 11:55
Probability that the first ball picked is odd numbered = total number of odd balls/ total number of balls = 50/100 = 1/2 Answer C
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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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08 Nov 2015, 12:07
Balls are numbered 1 to 100. that means 50 odd numbers and 50 even numbers. Then probability of selecting odd or even at first instance is 1/2. Hence answer is 1/2.



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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08 Nov 2015, 13:59
Probability of picking 1 even an 2 odd balls = 1/2 * 1/2 * 1/2 Now we have 2 repetitions of odd balls so we have to multiply the probability with 3!/2! Total probability = 1/2*1/2*1/2*3 =3/8
Probability of picking the 1st ball as odd = 1/2 * 1/2 * 1/2 Now the 2nd and 3rd draw could be counted in 2! ways. Also, we need to divide the entire equation by 2! since we have 2 repetitions (odd nos). So, total probability is 1/8.
This is a conditional probability. Given that we have 2 odd and 1 even ball, what is the probability of picking the 1st ball as odd
1/8 / 3/8 1/8 * 8/3 =1/3
Answer: B



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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08 Nov 2015, 16:39
A box contains 100 balls, numbered from 1 to 100. If 3 balls are selected at random and with replacement from the box. If the 3 numbers on the balls selected contain two odd and one even. What is the probability that the first ball picked up is odd numbered?
(A) 0 (B) 1/3 (C) 1/2 (D) 2/3 (E) 1
IMO B is correct As its stated out of 100 we have to chose 2 odd numbered and 1 even numbered ball so prob of this =(3!/2! )* 1/2 * 1/2 * 1/2 = 3/8 Now probability of choosing an odd ball = 1/2 * 1/2 * 1/2 =1/8
So probability of choosing odd ball at first place = (1/8)/( 3/8) = 1/3



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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08 Nov 2015, 18:16
probability of getting odd or even number is 1/2 we have 2 odds and 1 even. the probability of the first to be odd will thus be 1/2 * 2/3 or 1/3



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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08 Nov 2015, 18:33
IMO : C
As it's a case of replacement, each time one will have the same sample space and thus whether first or second or third pick is an odd numbered ball can simply calculated as
\(\frac{{count(1,3,5.....99)}}{{count(1,2,3,4....100)}}\) > \(\frac{50}{100}\) > \(\frac{1}{2}\).
Please correct if wrong. Vicky.



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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11 Nov 2015, 00:26
A box contains 100 balls, numbered from 1 to 100. If 3 balls are selected at random and with replacement from the box. If the 3 numbers on the balls selected contain two odd and one even. What is the probability that the first ball picked up is odd numbered?
(A) 0 (B) 1/3 (C) 1/2 (D) 2/3 (E) 1
AnswerD Selecting the balls either Even or Odd is having probability 50/100=1/2 We have already selected 3 balls with 2 odd numbers and 1 even number. So we have 3 combinations OOE, OEO, EOO. We have 3 outcomes and 2 are favourable as in 2 cases 1st number is odd. So probability is 2/3.



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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11 Nov 2015, 08:45
If three ball are selected order can be anything
here order is important. so 3 balls two odd and one even can be arranged in 3 ways.
first ball can be even number in 1 way...probability is 1/3
so first ball odd number is 11/3=2/3
so answer is option (D)



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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11 Nov 2015, 09:07
The question essentially asks the probability of getting the first ball as odd out of three possible outcomes: OOE, EOO, OEO. Here, we can see that the first ball is odd in two instances out of three. Therefore, the probability of getting the first ball as odd is: 2/3 Ans. D



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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11 Nov 2015, 10:32
Is it 2/3 ? D
Total numbers are 3, out of which 2 are odd and 1 is even.
so first number to be odd, it should be 2/3



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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11 Nov 2015, 11:29
P(odd)= 1/2 Probability of odd out of 3 (2 odd and 1 even) = 2/3 P(odd)*P(odd out of 3)= 1/2*2/3=1/3
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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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11 Nov 2015, 12:59
If the 3 numbers on the balls selected contain two odd and one even. The occurances can be O,O,E O,E,O E,O,O
So the probability that the first ball picked up is odd numbered is 2/3.........answer (D



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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12 Nov 2015, 11:31
Correct answer is D i.e. 2/3 because two odd and one even can be arranged in 3!/2!=3 ways OOE,OEO and EOO out of these only two cases are favorable. So probability will be 2/3



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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12 Nov 2015, 14:30
As per the given question, there are two "Odd" numbers and one "even" number picked.(with replacementthe most important part)
There for the scenarios can be
Odd, Odd, Even....(a) Odd, Even, Odd....(b) Even, Odd, Odd....(c)
Therefor for the first number to be odd, required probability
= 2/3 Option (D)



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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12 Nov 2015, 22:52
A box contains 100 balls, numbered from 1 to 100. If 3 balls are selected at random and with replacement from the box. If the 3 numbers on the balls selected contain two odd and one even. What is the probability that the first ball picked up is odd numbered?
(A) 0 (B) 1/3 (C) 1/2 (D) 2/3 (E) 1
Soln: All the middle part is irrelevent, since the probability of first ball being odd numbered is not affected by those. So the ans is 1/2 > C



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Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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12 Nov 2015, 23:11
1/2 Probability of 1st ball being odd= total no of odd balls divided by total no of balls in box = 50/100 = 1/2




Re: Jamboree and GMAT Club Contest: A box contains 100 balls, numbered
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