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nikhilv
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6 workers in all

# of ways to pick 2 people = 6C2 = 15 ways

# of ways James and Henry picked = 1

P = 1/15
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haas_mba07
Probability is not my strong suite... but here goes...

P(John) = 1/6
P(Henry) = 1/5 (out of 5 after John)
P(John & Henry) = 1/6 x 1/5 = 1/30


Your method is okay, but you need to multiply by two. This is becaue you considered only the case where John is picked first, then Henry. But Henry could be picked first, then John.

So you need 2 ( 1/6 * 1/5) = 1/15
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Number of ways HJ and JH
Probability of each is 1/30

Total P = 1/30 + 1/30 = 1/15
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haas_mba07
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ywilfred
haas_mba07
Probability is not my strong suite... but here goes...

P(John) = 1/6
P(Henry) = 1/5 (out of 5 after John)
P(John & Henry) = 1/6 x 1/5 = 1/30

Your method is okay, but you need to multiply by two. This is becaue you considered only the case where John is picked first, then Henry. But Henry could be picked first, then John.

So you need 2 ( 1/6 * 1/5) = 1/15


Thanks for the explanation, ywilfred. I definately need more pointers and help on Prob.



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