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05 May 2022, 08:30
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C
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Difficulty:
25%
(medium)
Question Stats:
59% (00:33) correct
41%
(00:42)
wrong
based on 93
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Jason flips a coin three times. What is the probability that the coin will land on the same side in all three tosses?
A. 1/16
B. 1/8
C. 1/4
D. 1/3
E. 1/2
A. 1/16
B. 1/8
C. 1/4
D. 1/3
E. 1/2
29 May 2022, 22:18
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Bunuel
There are 2 possibilities - 1) Either 3 Heads or 2 ) 3 Tails
Probability of 3 Heads = \(\frac{1}{2}\) * \(\frac{1}{2}\) * \(\frac{1}{2}\) = \(\frac{1}{8}\)
Similarly, Probability of 3 Tails = \(\frac{1}{8}\)
Probability of either 3 Heads or 3 Tails = \(\frac{1}{8}\) + \(\frac{1}{8}\) = \(\frac{1}{4}\)
Option C
29 Jul 2025, 07:27
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Jason flips a coin three times
Coin is tossed 3 times => Total number of cases = \(2^3\) = 8
What is the probability that it will land on the same side each time?
Lets solve the problem using two methods
Method 1:
Out of the 8 cases there are only two cases in which all the outcomes are same. HHH and TTT.
=> Probability that all three produce the same result = \(\frac{2}{8}\) = \(\frac{1}{4}\)
So, Answer will be B
Method 2:
Let's find out the number of cases.
In the first toss we can get anything out of head or tail in 2 ways
In second toss we need to get the same value (head or tail) as we got in the first toss => 1 way
In third toss we need to get the same value (head or tail) as we got in the second toss => 1 way
=> Total number of ways = 2*1*1 = 2 ways
=> Probability that all three produce the same result = \(\frac{2}{8}\) = \(\frac{1}{4}\)
So, Answer will be C
Hope it helps!
Playlist on Solved Problems on Probability here
Watch the following video to MASTER Probability with Coin Toss Problems
Coin is tossed 3 times => Total number of cases = \(2^3\) = 8
What is the probability that it will land on the same side each time?
Lets solve the problem using two methods
Method 1:
Out of the 8 cases there are only two cases in which all the outcomes are same. HHH and TTT.
=> Probability that all three produce the same result = \(\frac{2}{8}\) = \(\frac{1}{4}\)
So, Answer will be B
Method 2:
Let's find out the number of cases.
In the first toss we can get anything out of head or tail in 2 ways
In second toss we need to get the same value (head or tail) as we got in the first toss => 1 way
In third toss we need to get the same value (head or tail) as we got in the second toss => 1 way
=> Total number of ways = 2*1*1 = 2 ways
=> Probability that all three produce the same result = \(\frac{2}{8}\) = \(\frac{1}{4}\)
So, Answer will be C
Hope it helps!
Playlist on Solved Problems on Probability here
Watch the following video to MASTER Probability with Coin Toss Problems
