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Jim spent $60 purchasing lattes and coffees for his coworkers. If latt

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Jim spent $60 purchasing lattes and coffees for his coworkers. If latt  [#permalink]

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New post 17 Jan 2018, 00:09
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C
D
E

Difficulty:

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Question Stats:

88% (01:37) correct 12% (01:34) wrong based on 56 sessions

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Jim spent $60 purchasing lattes and coffees for his coworkers. If lattes cost $6 and coffees cost $3, and Jim purchased two more coffees than lattes, how many total drinks did he purchase?

A. 6
B. 8
C. 10
D. 12
E. 14

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Jim spent $60 purchasing lattes and coffees for his coworkers. If latt  [#permalink]

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New post 17 Jan 2018, 02:13
Bunuel wrote:
Jim spent $60 purchasing lattes and coffees for his coworkers. If lattes cost $6 and coffees cost $3, and Jim purchased two more coffees than lattes, how many total drinks did he purchase?

A. 6
B. 8
C. 10
D. 12
E. 14



From the question stem, we can get the following details
Let L be the number of lattes and C the number of coffees

\(6L + 3C = 60 -> (1)\)
As he purchases 2 more coffees than lattes,\(C = L + 2 -> (2)\)

Using (2) in (1), we get \(6L + 3(L + 2) = 60\)
\(9L + 6 = 60 => L = \frac{54}{9} = 6\) and \(C = L + 2 = 8\)

Therefore, the total number of drinks Jim purchased is 6+8 = 14(Option E)
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Jim spent $60 purchasing lattes and coffees for his coworkers. If latt  [#permalink]

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New post 21 Jan 2018, 14:21
Bunuel wrote:
Jim spent $60 purchasing lattes and coffees for his coworkers. If lattes cost $6 and coffees cost $3, and Jim purchased two more coffees than lattes, how many total drinks did he purchase?

A. 6
B. 8
C. 10
D. 12
E. 14

(# of coffees)(cost per coffee in $) +
(# of lattes)(cost per latte in $) = total cost in $ -->

(# of coffees)(3) + (# of lattes)(6) = 60

C = # of coffees
L = # of lattes
AND
# of coffees is 2 more than # of lattes:
C = L + 2

(C)(3) + (L)(6) = 60
(L + 2)(3) + 6L = 60
3L + 6 + 6L = 60
9L = 54
L = 6
C = L + 2
C = 8

Total # of drinks: 6 + 8 = 14

Answer E
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Re: Jim spent $60 purchasing lattes and coffees for his coworkers. If latt  [#permalink]

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New post 21 Jan 2018, 17:49
L = number of lattes
C = number of coffees

6L + 3C = 60 because problem states that lattes are $6, coffees are $3 and total cost is $60
C = L + 2 because there are two more coffees than lattes

Substitute, C = L + 2 into the equation 6L + 3C = 60
6L + 3(L + 2) = 60
9L = 54
L = 6
C = L + 2 = 6 + 2 = 8, hence C = 8

Problem is asking for total number of drinks so L + C = 8 + 6 = 14 total drinks (Option E)
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Re: Jim spent $60 purchasing lattes and coffees for his coworkers. If latt  [#permalink]

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New post 26 Feb 2018, 11:20
Bunuel wrote:
Jim spent $60 purchasing lattes and coffees for his coworkers. If lattes cost $6 and coffees cost $3, and Jim purchased two more coffees than lattes, how many total drinks did he purchase?

A. 6
B. 8
C. 10
D. 12
E. 14


We can let the number of lattes purchased = L and the number of coffees purchased = C, and create the equations:

60 = 6L + 3C

20 = 2L + C

20 - 2L = C

and

C = L + 2

Substituting, we have:

20 - 2L = L + 2

18 = 3L

6 = L, so C = 8

Thus, 6 + 8 = 14 total drinks were purchased.

Answer: E
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Re: Jim spent $60 purchasing lattes and coffees for his coworkers. If latt &nbs [#permalink] 26 Feb 2018, 11:20
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