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16 Jan 2018, 23:09
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25% (medium)

Question Stats:

76% (01:21) correct 24% (00:37) wrong based on 29 sessions

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Jim spent $60 purchasing lattes and coffees for his coworkers. If lattes cost$6 and coffees cost $3, and Jim purchased two more coffees than lattes, how many total drinks did he purchase? A. 6 B. 8 C. 10 D. 12 E. 14 [Reveal] Spoiler: OA _________________ BSchool Forum Moderator Joined: 26 Feb 2016 Posts: 2061 Location: India GPA: 3.12 Jim spent$60 purchasing lattes and coffees for his coworkers. If latt [#permalink]

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17 Jan 2018, 01:13
Bunuel wrote:
Jim spent $60 purchasing lattes and coffees for his coworkers. If lattes cost$6 and coffees cost $3, and Jim purchased two more coffees than lattes, how many total drinks did he purchase? A. 6 B. 8 C. 10 D. 12 E. 14 From the question stem, we can get the following details Let L be the number of lattes and C the number of coffees $$6L + 3C = 60 -> (1)$$ As he purchases 2 more coffees than lattes,$$C = L + 2 -> (2)$$ Using (2) in (1), we get $$6L + 3(L + 2) = 60$$ $$9L + 6 = 60 => L = \frac{54}{9} = 6$$ and $$C = L + 2 = 8$$ Therefore, the total number of drinks Jim purchased is 6+8 = 14(Option E) _________________ Stay hungry, Stay foolish 2017-2018 MBA Deadlines Class of 2020: Rotman Thread | Schulich Thread Class of 2019: Sauder Thread VP Joined: 22 May 2016 Posts: 1340 Jim spent$60 purchasing lattes and coffees for his coworkers. If latt [#permalink]

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21 Jan 2018, 13:21
Bunuel wrote:
Jim spent $60 purchasing lattes and coffees for his coworkers. If lattes cost$6 and coffees cost $3, and Jim purchased two more coffees than lattes, how many total drinks did he purchase? A. 6 B. 8 C. 10 D. 12 E. 14 (# of coffees)(cost per coffee in$) +
(# of lattes)(cost per latte in $) = total cost in$ -->

(# of coffees)(3) + (# of lattes)(6) = 60

C = # of coffees
L = # of lattes
AND
# of coffees is 2 more than # of lattes:
C = L + 2

(C)(3) + (L)(6) = 60
(L + 2)(3) + 6L = 60
3L + 6 + 6L = 60
9L = 54
L = 6
C = L + 2
C = 8

Total # of drinks: 6 + 8 = 14

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Posts: 32
Re: Jim spent $60 purchasing lattes and coffees for his coworkers. If latt [#permalink] ### Show Tags 21 Jan 2018, 16:49 L = number of lattes C = number of coffees 6L + 3C = 60 because problem states that lattes are$6, coffees are $3 and total cost is$60
C = L + 2 because there are two more coffees than lattes

Substitute, C = L + 2 into the equation 6L + 3C = 60
6L + 3(L + 2) = 60
9L = 54
L = 6
C = L + 2 = 6 + 2 = 8, hence C = 8

Problem is asking for total number of drinks so L + C = 8 + 6 = 14 total drinks (Option E)