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17 Jan 2018, 00:09
00:00

Difficulty:

15% (low)

Question Stats:

88% (01:37) correct 12% (01:34) wrong based on 56 sessions

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Jim spent $60 purchasing lattes and coffees for his coworkers. If lattes cost$6 and coffees cost $3, and Jim purchased two more coffees than lattes, how many total drinks did he purchase? A. 6 B. 8 C. 10 D. 12 E. 14 _________________ Senior PS Moderator Joined: 26 Feb 2016 Posts: 3182 Location: India GPA: 3.12 Jim spent$60 purchasing lattes and coffees for his coworkers. If latt  [#permalink]

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17 Jan 2018, 02:13
Bunuel wrote:
Jim spent $60 purchasing lattes and coffees for his coworkers. If lattes cost$6 and coffees cost $3, and Jim purchased two more coffees than lattes, how many total drinks did he purchase? A. 6 B. 8 C. 10 D. 12 E. 14 From the question stem, we can get the following details Let L be the number of lattes and C the number of coffees $$6L + 3C = 60 -> (1)$$ As he purchases 2 more coffees than lattes,$$C = L + 2 -> (2)$$ Using (2) in (1), we get $$6L + 3(L + 2) = 60$$ $$9L + 6 = 60 => L = \frac{54}{9} = 6$$ and $$C = L + 2 = 8$$ Therefore, the total number of drinks Jim purchased is 6+8 = 14(Option E) _________________ You've got what it takes, but it will take everything you've got Senior SC Moderator Joined: 22 May 2016 Posts: 2033 Jim spent$60 purchasing lattes and coffees for his coworkers. If latt  [#permalink]

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21 Jan 2018, 14:21
Bunuel wrote:
Jim spent $60 purchasing lattes and coffees for his coworkers. If lattes cost$6 and coffees cost $3, and Jim purchased two more coffees than lattes, how many total drinks did he purchase? A. 6 B. 8 C. 10 D. 12 E. 14 (# of coffees)(cost per coffee in$) +
(# of lattes)(cost per latte in $) = total cost in$ -->

(# of coffees)(3) + (# of lattes)(6) = 60

C = # of coffees
L = # of lattes
AND
# of coffees is 2 more than # of lattes:
C = L + 2

(C)(3) + (L)(6) = 60
(L + 2)(3) + 6L = 60
3L + 6 + 6L = 60
9L = 54
L = 6
C = L + 2
C = 8

Total # of drinks: 6 + 8 = 14

_________________

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Intern
Joined: 28 Dec 2017
Posts: 31
Re: Jim spent $60 purchasing lattes and coffees for his coworkers. If latt [#permalink] ### Show Tags 21 Jan 2018, 17:49 L = number of lattes C = number of coffees 6L + 3C = 60 because problem states that lattes are$6, coffees are $3 and total cost is$60
C = L + 2 because there are two more coffees than lattes

Substitute, C = L + 2 into the equation 6L + 3C = 60
6L + 3(L + 2) = 60
9L = 54
L = 6
C = L + 2 = 6 + 2 = 8, hence C = 8

Problem is asking for total number of drinks so L + C = 8 + 6 = 14 total drinks (Option E)
Target Test Prep Representative
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2830
Re: Jim spent $60 purchasing lattes and coffees for his coworkers. If latt [#permalink] ### Show Tags 26 Feb 2018, 11:20 Bunuel wrote: Jim spent$60 purchasing lattes and coffees for his coworkers. If lattes cost $6 and coffees cost$3, and Jim purchased two more coffees than lattes, how many total drinks did he purchase?

A. 6
B. 8
C. 10
D. 12
E. 14

We can let the number of lattes purchased = L and the number of coffees purchased = C, and create the equations:

60 = 6L + 3C

20 = 2L + C

20 - 2L = C

and

C = L + 2

Substituting, we have:

20 - 2L = L + 2

18 = 3L

6 = L, so C = 8

Thus, 6 + 8 = 14 total drinks were purchased.

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