John had to multiply two positive integers. Instead of taking 35 as on

Question

John had to multiply two positive integers. Instead of taking 35 as one of the multipliers, he incorrectly took 53. As a result, the product went up by 540. What is the new product?

A. 1050
B. 540
C. 1440
D. 1520
E. 1590

Mohammadmo · Answer

53X= 35X+540
18X=540
X=30
30*53=1590
Option E

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Nitisha03 · Answer

Other way around is to look at the answer choice and find the multiple of 53. Only 1590 is divisible by 53.

Simple way is to check if the last 2 digits will be divisible by 3 or not as the XX00 will always be divisible by 50.

SSG12 · Answer

Solution -

Here, we have to consider two positive integers. It is given in the question that, instead of taking 35 as one of the multipliers, John incorrectly took it as 53. 
Let, one of the integers be considered as “x”
So, we can represent this as – 
(53)(x) = (35)(x) + 540
=> (18)(x) = 540
∴ x=30
New Product = 53 ×30=1590
Answer – E
There is another way to look at the answer choice and find which of them is a multiple of 53. Among these answer choices, 1590 is divisible by 53.

bumpbot · Answer

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John had to multiply two positive integers. Instead of taking 35 as on

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