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John will spend the summer in one of the houses either on Surf Street
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23 May 2019, 04:26
Question Stats:
41% (02:40) correct 59% (02:36) wrong based on 34 sessions
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John will spend the summer in one of the houses either on Surf Street or Breaker Way. Surf Street has 1 landside house and 4 beachside houses, and Breaker Way has 1 beachside house and 2 landside houses. A sea turtle randomly lays eggs in front of a beachside house on Surf Street, and another sea turtle randomly lays eggs in front of a beachside house on Breaker Way. What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on? I. 1/5 II. 4/15 III. 1/3 A. I only B. II only C. III only D. I and III only E. I, II and III
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Re: John will spend the summer in one of the houses either on Surf Street
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23 May 2019, 13:22
Bunuel wrote: John will spend the summer in one of the houses either on Surf Street or Breaker Way. Surf Street has 1 landside house and 4 beachside houses, and Breaker Way has 1 beachside house and 2 landside houses. A sea turtle randomly lays eggs in front of a beachside house on Surf Street, and another sea turtle randomly lays eggs in front of a beachside house on Breaker Way. What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on?
I. 1/5 II. 4/15 III. 1/3
A. I only B. II only C. III only D. I and III only E. I, II and III There are 5 houses on Surf street ( 1L,4B) and 3 houses on Breakway Street (2L,1B). Now John can live in any one of the house. If he lives in Surf street , possible outcomes  5 (1L,4B) .Therefore Probablity(Surfstreet) = 1/5 Similary, If he lives in Breakway street , possible outcomes  3(2L,1B) , Probablity(Surfstreet) = 1/5 Hence 1/5 , 1/3 are possible probabilities depending upon where John lives.Correct Option D
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Re: John will spend the summer in one of the houses either on Surf Street
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23 May 2019, 17:38
I have one doubt here.
Question stem already says that the turtle lays its egg in front of the beach house. And Now question is asking the probability of laying the egg in front of the John's house. Therefore, we have to calculate the probability of living of John in Beach house where turtle will lay its egg.
From that point, only 4/5 and 1/3 is correct choice. 1/3 is in options. Therefore, only C is correct.



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Re: John will spend the summer in one of the houses either on Surf Street
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24 May 2019, 01:01
gvij2017 wrote: I have one doubt here.
Question stem already says that the turtle lays its egg in front of the beach house. And Now question is asking the probability of laying the egg in front of the John's house. Therefore, we have to calculate the probability of living of John in Beach house where turtle will lay its egg.
From that point, only 4/5 and 1/3 is correct choice. 1/3 is in options. Therefore, only C is correct. I think you missed the question " What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on? " John can live in one of the beach house in one of the street. So our successful case will be 1 (1 beach house , either on Surf or Breakway street) always and possible cases will be sum of land and beach houses. Hope it helps.
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Re: John will spend the summer in one of the houses either on Surf Street
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27 May 2019, 19:10
Bunuel wrote: John will spend the summer in one of the houses either on Surf Street or Breaker Way. Surf Street has 1 landside house and 4 beachside houses, and Breaker Way has 1 beachside house and 2 landside houses. A sea turtle randomly lays eggs in front of a beachside house on Surf Street, and another sea turtle randomly lays eggs in front of a beachside house on Breaker Way. What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on?
I. 1/5 II. 4/15 III. 1/3
A. I only B. II only C. III only D. I and III only E. I, II and III If John is staying at a house on Surf Street, then the probability is 4/5 x 1/4 = 1/5 that the turtle will lay eggs in front of John’s house (notice that 4/5 is the probability John will stay at a beachside house and 1/4 is the probability the turtle will lay eggs at the house in which John is staying). If John is staying at a house on Breaker Way, then the probability is 1/3 x 1/1 = 1/1 that it will lay eggs in front of John’s house (notice that 1/3 is the probability John will stay at a beachside house and 1/1 is the probability the turtle will lay eggs at the house in which John is staying).. Answer: D
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Re: John will spend the summer in one of the houses either on Surf Street
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31 May 2019, 03:24
ScottTargetTestPrep wrote: Bunuel wrote: John will spend the summer in one of the houses either on Surf Street or Breaker Way. Surf Street has 1 landside house and 4 beachside houses, and Breaker Way has 1 beachside house and 2 landside houses. A sea turtle randomly lays eggs in front of a beachside house on Surf Street, and another sea turtle randomly lays eggs in front of a beachside house on Breaker Way. What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on?
I. 1/5 II. 4/15 III. 1/3
A. I only B. II only C. III only D. I and III only E. I, II and III If John is staying at a house on Surf Street, then the probability is 4/5 x 1/4 = 1/5 that the turtle will lay eggs in front of John’s house (notice that 4/5 is the probability John will stay at a beachside house and 1/4 is the probability the turtle will lay eggs at the house in which John is staying). If John is staying at a house on Breaker Way, then the probability is 1/3 x 1/1 = 1/1 that it will lay eggs in front of John’s house (notice that 1/3 is the probability John will stay at a beachside house and 1/1 is the probability the turtle will lay eggs at the house in which John is staying).. Answer: D Hi Scott, I'm sorry, I still don't understand this, why are we not adding the two 'OR' probabilities here? I know that's not an answer option, but that's where I got stuck. Since John will EITHER live in Surf Street OR in Breaker Way.



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John will spend the summer in one of the houses either on Surf Street
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11 Jun 2019, 12:06
rishabhjain13 wrote: ScottTargetTestPrep wrote: Bunuel wrote: John will spend the summer in one of the houses either on Surf Street or Breaker Way. Surf Street has 1 landside house and 4 beachside houses, and Breaker Way has 1 beachside house and 2 landside houses. A sea turtle randomly lays eggs in front of a beachside house on Surf Street, and another sea turtle randomly lays eggs in front of a beachside house on Breaker Way. What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on?
I. 1/5 II. 4/15 III. 1/3
A. I only B. II only C. III only D. I and III only E. I, II and III If John is staying at a house on Surf Street, then the probability is 4/5 x 1/4 = 1/5 that the turtle will lay eggs in front of John’s house (notice that 4/5 is the probability John will stay at a beachside house and 1/4 is the probability the turtle will lay eggs at the house in which John is staying). If John is staying at a house on Breaker Way, then the probability is 1/3 x 1/1 = 1/1 that it will lay eggs in front of John’s house (notice that 1/3 is the probability John will stay at a beachside house and 1/1 is the probability the turtle will lay eggs at the house in which John is staying).. Answer: D Hi Scott, I'm sorry, I still don't understand this, why are we not adding the two 'OR' probabilities here? I know that's not an answer option, but that's where I got stuck. Since John will EITHER live in Surf Street OR in Breaker Way. I believe we're not adding the two because the question says "depending on which street he stays" i.e. The question is asking us to consider that he stays in one of the street, now calculate the probability that he is staying in a particular house of that street. Am I right @buneul?




John will spend the summer in one of the houses either on Surf Street
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