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John will spend the summer in one of the houses either on Surf Street

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Bunuel
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John will spend the summer in one of the houses either on Surf Street [#permalink] New post   23 May 2019, 04:26
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John will spend the summer in one of the houses either on Surf Street or Breaker Way. Surf Street has 1 landside house and 4 beachside houses, and Breaker Way has 1 beachside house and 2 landside houses. A sea turtle randomly lays eggs in front of a beachside house on Surf Street, and another sea turtle randomly lays eggs in front of a beachside house on Breaker Way. What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on?

I. 1/5
II. 4/15
III. 1/3


A. I only
B. II only
C. III only
D. I and III only
E. I, II and III
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D
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ScottTargetTestPrep
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Re: John will spend the summer in one of the houses either on Surf Street [#permalink] New post   27 May 2019, 19:10
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Bunuel wrote:
John will spend the summer in one of the houses either on Surf Street or Breaker Way. Surf Street has 1 landside house and 4 beachside houses, and Breaker Way has 1 beachside house and 2 landside houses. A sea turtle randomly lays eggs in front of a beachside house on Surf Street, and another sea turtle randomly lays eggs in front of a beachside house on Breaker Way. What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on?

I. 1/5
II. 4/15
III. 1/3


A. I only
B. II only
C. III only
D. I and III only
E. I, II and III


If John is staying at a house on Surf Street, then the probability is 4/5 x 1/4 = 1/5 that the turtle will lay eggs in front of John’s house (notice that 4/5 is the probability John will stay at a beachside house and 1/4 is the probability the turtle will lay eggs at the house in which John is staying).
If John is staying at a house on Breaker Way, then the probability is 1/3 x 1/1 = 1/1 that it will lay eggs in front of John’s house (notice that 1/3 is the probability John will stay at a beachside house and 1/1 is the probability the turtle will lay eggs at the house in which John is staying)..

Answer: D
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Re: John will spend the summer in one of the houses either on Surf Street [#permalink] New post   23 May 2019, 13:22
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Bunuel wrote:
John will spend the summer in one of the houses either on Surf Street or Breaker Way. Surf Street has 1 landside house and 4 beachside houses, and Breaker Way has 1 beachside house and 2 landside houses. A sea turtle randomly lays eggs in front of a beachside house on Surf Street, and another sea turtle randomly lays eggs in front of a beachside house on Breaker Way. What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on?

I. 1/5
II. 4/15
III. 1/3


A. I only
B. II only
C. III only
D. I and III only
E. I, II and III


There are 5 houses on Surf street ( 1L,4B) and 3 houses on Breakway Street (2L,1B). Now John can live in any one of the house.
If he lives in Surf street , possible outcomes - 5 (1L,4B) .Therefore Probablity(Surfstreet) = 1/5
Similary, If he lives in Breakway street , possible outcomes - 3(2L,1B) , Probablity(Surfstreet) = 1/5

Hence 1/5 , 1/3 are possible probabilities depending upon where John lives.

Correct Option D
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Re: John will spend the summer in one of the houses either on Surf Street [#permalink] New post   23 May 2019, 17:38
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I have one doubt here.

Question stem already says that the turtle lays its egg in front of the beach house. And Now question is asking the probability of laying the egg in front of the John's house. Therefore, we have to calculate the probability of living of John in Beach house where turtle will lay its egg.

From that point, only 4/5 and 1/3 is correct choice. 1/3 is in options. Therefore, only C is correct.
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Re: John will spend the summer in one of the houses either on Surf Street [#permalink] New post   24 May 2019, 01:01
gvij2017 wrote:
I have one doubt here.

Question stem already says that the turtle lays its egg in front of the beach house. And Now question is asking the probability of laying the egg in front of the John's house. Therefore, we have to calculate the probability of living of John in Beach house where turtle will lay its egg.

From that point, only 4/5 and 1/3 is correct choice. 1/3 is in options. Therefore, only C is correct.


I think you missed the question " What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on? "

John can live in one of the beach house in one of the street. So our successful case will be 1 (1 beach house , either on Surf or Breakway street) always and possible cases will be sum of land and beach houses.

Hope it helps.
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Re: John will spend the summer in one of the houses either on Surf Street [#permalink] New post   31 May 2019, 03:24
ScottTargetTestPrep wrote:
Bunuel wrote:
John will spend the summer in one of the houses either on Surf Street or Breaker Way. Surf Street has 1 landside house and 4 beachside houses, and Breaker Way has 1 beachside house and 2 landside houses. A sea turtle randomly lays eggs in front of a beachside house on Surf Street, and another sea turtle randomly lays eggs in front of a beachside house on Breaker Way. What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on?

I. 1/5
II. 4/15
III. 1/3


A. I only
B. II only
C. III only
D. I and III only
E. I, II and III


If John is staying at a house on Surf Street, then the probability is 4/5 x 1/4 = 1/5 that the turtle will lay eggs in front of John’s house (notice that 4/5 is the probability John will stay at a beachside house and 1/4 is the probability the turtle will lay eggs at the house in which John is staying).
If John is staying at a house on Breaker Way, then the probability is 1/3 x 1/1 = 1/1 that it will lay eggs in front of John’s house (notice that 1/3 is the probability John will stay at a beachside house and 1/1 is the probability the turtle will lay eggs at the house in which John is staying)..

Answer: D


Hi Scott,

I'm sorry, I still don't understand this, why are we not adding the two 'OR' probabilities here? I know that's not an answer option, but that's where I got stuck. Since John will EITHER live in Surf Street OR in Breaker Way.
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John will spend the summer in one of the houses either on Surf Street [#permalink] New post   11 Jun 2019, 12:06
rishabhjain13 wrote:
ScottTargetTestPrep wrote:
Bunuel wrote:
John will spend the summer in one of the houses either on Surf Street or Breaker Way. Surf Street has 1 landside house and 4 beachside houses, and Breaker Way has 1 beachside house and 2 landside houses. A sea turtle randomly lays eggs in front of a beachside house on Surf Street, and another sea turtle randomly lays eggs in front of a beachside house on Breaker Way. What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on?

I. 1/5
II. 4/15
III. 1/3


A. I only
B. II only
C. III only
D. I and III only
E. I, II and III


If John is staying at a house on Surf Street, then the probability is 4/5 x 1/4 = 1/5 that the turtle will lay eggs in front of John’s house (notice that 4/5 is the probability John will stay at a beachside house and 1/4 is the probability the turtle will lay eggs at the house in which John is staying).
If John is staying at a house on Breaker Way, then the probability is 1/3 x 1/1 = 1/1 that it will lay eggs in front of John’s house (notice that 1/3 is the probability John will stay at a beachside house and 1/1 is the probability the turtle will lay eggs at the house in which John is staying)..

Answer: D


Hi Scott,

I'm sorry, I still don't understand this, why are we not adding the two 'OR' probabilities here? I know that's not an answer option, but that's where I got stuck. Since John will EITHER live in Surf Street OR in Breaker Way.



I believe we're not adding the two because the question says "depending on which street he stays"
i.e. The question is asking us to consider that he stays in one of the street, now calculate the probability that he is staying in a particular house of that street.
Am I right @buneul?
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Re: John will spend the summer in one of the houses either on Surf Street [#permalink] New post   29 Sep 2019, 11:48
Bunuel wrote:
John will spend the summer in one of the houses either on Surf Street or Breaker Way. Surf Street has 1 landside house and 4 beachside houses, and Breaker Way has 1 beachside house and 2 landside houses. A sea turtle randomly lays eggs in front of a beachside house on Surf Street, and another sea turtle randomly lays eggs in front of a beachside house on Breaker Way. What are the probabilities that a sea turtle lays its eggs in front of John`s house, depending on which street he lives on?

I. 1/5
II. 4/15
III. 1/3


A. I only
B. II only
C. III only
D. I and III only
E. I, II and III


Probably a very silly thing point here. But we have 2 streets where john can live. So there will be 2 probabilities no matter what. Now only answer D has 2 probabilities.
All 3 cannot be and we cannot have one. If the options would have been A. I,II B. II,III C. I,III then it would have made sense to even calculate.?
Kindly help me understand.

P.S: Please assume I am thinking out loud.

Thank you.!
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Re: John will spend the summer in one of the houses either on Surf Street [#permalink] New post   04 Oct 2019, 19:32
TheNightKing
Both could have the same probability so A, B and C are in. I don't think 3 probabilities is an option though
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Re: John will spend the summer in one of the houses either on Surf Street [#permalink] New post   04 Oct 2019, 20:24
philipssonicare wrote:
TheNightKing
Both could have the same probability so A, B and C are in. I don't think 3 probabilities is an option though


Yeah I realised that later on. But still you can play your odds if you can't solve :) Just saying and not encouraging to go that route.!
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Re: John will spend the summer in one of the houses either on Surf Street [#permalink] New post   09 Dec 2020, 08:12
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Re: John will spend the summer in one of the houses either on Surf Street [#permalink]
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