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MBAlad
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MBAlad
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ncp
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I get the exact same question 1 and I got it wrong :-D


I miss the power of power. :oops:
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Work the powers

(4-1)(4-1) = 16-4-4+1 = 9 = TOP HALF = 2^9 THEN IT 2^9 - 2^1 = 2^8

Hope I get something like this on the real GMAT, taken it a few times, and always get a standard deviation to start with!
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MBAlad
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OA is A - well done guys

So to follow on:

If d=2^64 and p=2^3

p^d = ??
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mbagal1
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Hi,

That would be: 2^(3*(2^64))

MBAlad
OA is A - well done guys

So to follow on:

If d=2^64 and p=2^3

p^d = ??
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MBAlad
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Can you simplify it further?
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guys if the numerator is 2^(2)^3 it is 2^6 right


This thing killed me last time in gmat
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mbagal1
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MBAlad
Can you simplify it further?


Not sure how you could do that, I mean 2^64 is just that, and the multiple 3* 2^64, cannot really be simplified.

Of course, 2^(3*(2^64)) = 8^(2^64)
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trivikram
guys if the numerator is 2^(2)^3 it is 2^6 right


This thing killed me last time in gmat


No, that would be 2^8

2^(2^3) = 2^8
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hsampath
trivikram
guys if the numerator is 2^(2)^3 it is 2^6 right


This thing killed me last time in gmat

No, that would be 2^8

2^(2^3) = 2^8


OK

so (2^3)^2 = 2^6?
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I almost thought you were wrong with that, but it turns out you are right.


trivikram
hsampath
trivikram
guys if the numerator is 2^(2)^3 it is 2^6 right


This thing killed me last time in gmat

No, that would be 2^8

2^(2^3) = 2^8

OK

so (2^3)^2 = 2^6?
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A. 2^8

remember: a^b^c = a^(b^c) ..always

not (a^b)^c



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