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# Kim has 40 percent more money than Sal and Sal has 20 percent less mon

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Joined: 27 Sep 2015
Posts: 55
GMAT 1: 410 Q33 V13
WE: Management Consulting (Computer Software)
Kim has 40 percent more money than Sal and Sal has 20 percent less mon  [#permalink]

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22 Dec 2015, 14:56
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1
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Difficulty:

25% (medium)

Question Stats:

76% (02:00) correct 24% (02:13) wrong based on 216 sessions

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Kim has 40 percent more money than Sal and Sal has 20 percent less money than Phil. If Sal and Phil have a combined total of $1.80, how much money does Kim have? (A)$1.00
(B) $1.12 (C)$1.20
(D) $1.32 (E)$1.40

Source: Test 55, S7, Q12, P28

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Re: Kim has 40 percent more money than Sal and Sal has 20 percent less mon  [#permalink]

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29 Dec 2015, 21:22
1
Phil = x
Sal = 0.8x
Kim = (1.4)*0.8x = 1.12x

x + 0.8x = 1.8 --> x = 1
Kim = 1.12

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Re: Kim has 40 percent more money than Sal and Sal has 20 percent less mon  [#permalink]

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02 Jan 2016, 19:01
Hi All,

This question has a really subtle Number Property rule built into it - THAT rule, when combined with TESTing THE ANSWERS, can help you to quickly answer this question.

First, it's worth noting that answer choices all involve 'cents' as part of the formatting, so we have to calculate down to the penny. We're told that Kim has 40% more money than Sal....Algebraically, that means...

K = 1.4(S)

1.4 = 14/10 = 7/5, so in real-world terms, that means for every 5 cents that Sal has, Kim has 7 cents. This is useful information, since the prompt asks for the amount of money that KIM has and now we know that she has some multiple of 7 cents. Working through the answer choices, there are ONLY 2 answers that are a multiple of 7 cents: Answers B and E. Answer E seems like the 'nicer' answer, so I'll TEST that one first...

Answer E: $1.40 IF.... Kim =$1.40
Sal = $1.00 We're told that Sal has 20% less money than Phil, which would mean that Phil has MORE than$1.00. Combined, Sal and Phil would total OVER $2.00, but the prompt states that their total is$1.80. Since this clearly does NOT match up with what we're told, Answer E is incorrect, which leaves just one answer...

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Rich
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Re: Kim has 40 percent more money than Sal and Sal has 20 percent less mon  [#permalink]

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17 May 2016, 11:12
RSOHAL wrote:
Kim has 40 percent more money than Sal and Sal has 20 percent less money than Phil. If Sal and Phil have a combined total of $1.80, how much money does Kim have? (A)$1.00
(B) $1.12 (C)$1.20
(D) $1.32 (E)$1.40

Source: Test 55, S7, Q12, P28

K=(1+40/100)S
S=(1-20/100)P-------(a)
given S+P=1.8
add P on both sides of (a)
1.8=(1-20/100+1)P
P=1
so,S=0.8
As K=(1+40/100)S
putting S=0.8
gives K=1.12
Ans B
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Kim has 40 percent more money than Sal and Sal has 20 percent less mon  [#permalink]

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23 Jun 2018, 20:35
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RSOHAL wrote:
Kim has 40 percent more money than Sal and Sal has 20 percent less money than Phil. If Sal and Phil have a combined total of $1.80, how much money does Kim have? (A)$1.00
(B) $1.12 (C)$1.20
(D) $1.32 (E)$1.40

Source: Test 55, S7, Q12, P28

If ratios are involved (A has X percent more or less than B = a ratio), the moment we see a "counting number" we should pounce.

Sal and Phil have a combined total of $1.80. Thus: $$(S+P)=1.80$$ And: Sal has 20 percent less money than Phil: $$S = 0.80P$$ Substitute that value for $$S$$. Now we have $$0.8P+P=1.80$$ $$1.8P=1.80$$ $$P=\frac{1.80}{1.8}=1.00$$ Sal? $$S=0.80P=(0.8*1.00)=0.80$$ Kim? She has 40 percent more money than Sal. $$K=1.4S$$ $$K=(1.4*0.80)=1.12$$ Answer B _________________ SC Butler has resumed! Get two SC questions to practice, whose links you can find by date, here. Choose life. GMAT Club Legend Joined: 12 Sep 2015 Posts: 4000 Location: Canada Re: Kim has 40 percent more money than Sal and Sal has 20 percent less mon [#permalink] ### Show Tags 24 Feb 2019, 09:54 Top Contributor RSOHAL wrote: Kim has 40 percent more money than Sal and Sal has 20 percent less money than Phil. If Sal and Phil have a combined total of$1.80, how much money does Kim have?

(A) $1.00 (B)$1.12
(C) $1.20 (D)$1.32
(E) $1.40 Source: Test 55, S7, Q12, P28 Let x = Phil's money Sal has 20 percent LESS money than Phil So, Sal's money = (Phil's money) - (20% of Phil's money) = x - (20% of x) = x - 0.2x = 0.8x Kim has 40 percent more money than Sal So, Kim's money = (Sal's money) + (40% of Sal's money) = (0.8x) + (40% of 0.8x) = (0.8x) + (0.4)(0.8x) = 0.8x + 0.32x = 1.12x If Sal and Phil have a combined total of$1.80, how much money does Kim have?
We can write: 0.8x + x = 1.80
Simplify: 1.8x = 1.80
Solve: x = 1.80/1.8 = 1

We know that Kim's money = 1.12x
Since x = 1, we get: 1.12(1) = 1.12

Cheers,
Brent
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Re: Kim has 40 percent more money than Sal and Sal has 20 percent less mon  [#permalink]

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09 Mar 2019, 03:26
P =100,S= 80,K= 80*120/100= 112 ( assume).
P+S= 100+80= 180
So k = 1.8*112/180= 1.12

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Re: Kim has 40 percent more money than Sal and Sal has 20 percent less mon   [#permalink] 09 Mar 2019, 03:26
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