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thearch
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lailalalalaiiiiaiaiaiai 04 Jun 2005, 09:04
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lailalalalaiiiiaiaiaiai 04 Jun 2005, 09:40
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E.

21 cons, 5 vowels, and no specific slot!

21C3 * 5C1 * 4!
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HowManyToGo
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lailalalalaiiiiaiaiaiai 04 Jun 2005, 12:11
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Dan
E.

21 cons, 5 vowels, and no specific slot!

21C3 * 5C1 * 4!
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Don't fall for the trap !

I vote for C ( added later ,forgot earlier) !

This is not a the typical combination problem as repetitions are allowed.
So ,the vovel can be chosen in 5 ways and the 3 consonants in 21^3 ways ( as repetition is allowed).
Hence total no. of ways is 21^3 * 5 * 4!

HMTG.
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lailalalalaiiiiaiaiaiai 04 Jun 2005, 12:26
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Dan
E.

21 cons, 5 vowels, and no specific slot!

21C3 * 5C1 * 4!

Don't fall for the trap !

I vote for C ( added later ,forgot earlier) !

This is not a the typical combination problem as repetitions are allowed.
So ,the vovel can be chosen in 5 ways and the 3 consonants in 21^3 ways ( as repetition is allowed).
Hence total no. of ways is 21^3 * 5 * 4!

HMTG.
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But here if repetitions are allowed then how did you get 4! directly?

Suppose you have a,s,t,t

it is 4!/2! right? Silimarly should'nt we take care of the rest?
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lailalalalaiiiiaiaiaiai 04 Jun 2005, 13:22
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If repetition is allowed, it's D, 21*21*21*5*4C3 (don't forget 4C3 = 4C1)
if no repetition it's E. 21C3 * 5C1 * 4!
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lailalalalaiiiiaiaiaiai 04 Jun 2005, 14:31
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i would go for 21C1*21C1*21C1*5C1*4!

i.e. 21^3*5*4!
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lailalalalaiiiiaiaiaiai 04 Jun 2005, 21:09
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sparky
If repetition is allowed, it's D, 21*21*21*5*4C3 (don't forget 4C3 = 4C1)
if no repetition it's E. 21C3 * 5C1 * 4!
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I agree.

My answer above is with no repetition
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lailalalalaiiiiaiaiaiai 05 Jun 2005, 02:48
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sparky
If repetition is allowed, it's D, 21*21*21*5*4C3 (don't forget 4C3 = 4C1)
if no repetition it's E. 21C3 * 5C1 * 4!
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:done
OA is D
Could you please explain why 4c3?
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lailalalalaiiiiaiaiaiai 05 Jun 2005, 13:23
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sparky
If repetition is allowed, it's D, 21*21*21*5*4C3 (don't forget 4C3 = 4C1)
if no repetition it's E. 21C3 * 5C1 * 4!

:done
OA is D
Could you please explain why 4c3?
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21^3 already takes into account order (since you draw from the same set).

but 5 doesn't. so you need to multiply by 4C1=4C3 to account for all possible 'sticking' of the vowel between or on the side of consonants.
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lailalalalaiiiiaiaiaiai 05 Jun 2005, 13:54
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Basically you pick three position from the four positions for the consonants, or pick one position for the vowel.



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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