last one , last one, last one, ......for today Can someone

Question

last one , last one, last one, ......for today

Can someone EXPLAIN how to approach it, PLEASE!

mNeo · Answer

Statement 1 itself is obviously not sufficient.

Now, statement 2 gives a possibility that the n's slope can be compared to p's if we know in which quadrant the lines intersect. For example, if they intersect in quadrant 1, then the n's slope is going to be greater than p (For it to have a greater y intersect).

Intersection point (5,1) lies in the 1st quadrant. Hence the two statements together are sufficient, but not alone

I hope I am correct :roll:

riverripper · Answer

Drawing these out makes all the difference.

Do the X/Y graph. Put a dot on (5,1) Then pick an arbitrary point on Y. Use the origin (0,0) Call that N intercept. Pick a point below the N intercept, call that P intersect. Connect the dots. N to (5,1) and P to (5,1) look at the slopes of the lines that gives you the answer. 

Look at what you drew for the first statement, it doesnt give you a slope at all. Its a point not a line.
Look at what you drew for the second statement, same thing as the first...no line so no slope.

Combining the two and it works. So both statements together is sufficient but neither is enough by itself.

ywilfred · Answer

st1 is useless on its own.
st2 is useless on its own too. if both n and p are positive/negative sloping lines, then yes, n is steeper than p. but if n is negative sloping and p is positive sloping, then the graident of p is greater than n.

using st1 and st2, we have two points for each line now (5,1) and (0,a) for line n and (0,b) for line p where a>b. You can derive the gradient for both lines n and p now to answer the question. (Note: you don't have to physically solve the question. just click and go!!. But if you want to convince yourself, just plug valid values of a and b)

seofah · Answer

Assuming we are considering both statements together:

y=nx+b
y1=px+b1

So, arithmetically I am getting that the question is asking whether n<p
am I right? Otherwise, OA C would not make sense

last one , last one, last one, ......for today Can someone

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