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# Last year, Christine received 12 monthly paychecks. Each of the first

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Math Expert
Joined: 02 Sep 2009
Posts: 52231
Last year, Christine received 12 monthly paychecks. Each of the first  [#permalink]

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27 Mar 2017, 02:26
00:00

Difficulty:

5% (low)

Question Stats:

92% (01:38) correct 8% (01:34) wrong based on 53 sessions

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Last year, Christine received 12 monthly paychecks. Each of the first four months’ paychecks was for $4500, and each of the remaining months’ paychecks was for$4800. What was her average paycheck for the year?

A. $4600 B.$4650
C. $4700 D.$4750
E. $4800 _________________ CEO Joined: 11 Sep 2015 Posts: 3331 Location: Canada Last year, Christine received 12 monthly paychecks. Each of the first [#permalink] ### Show Tags Updated on: 15 Apr 2018, 15:22 Top Contributor Bunuel wrote: Last year, Christine received 12 monthly paychecks. Each of the first four months’ paychecks was for$4500, and each of the remaining months’ paychecks was for $4800. What was her average paycheck for the year? A.$4600
B. $4650 C.$4700
D. $4750 E.$4800

One approach:
Total pay = 4($4500) + 8($4800)
= $56,400 So, average of all 12 paychecks =$56,400/12 = $4700 Answer: RELATED VIDEO _________________ Test confidently with gmatprepnow.com Originally posted by GMATPrepNow on 27 Mar 2017, 07:20. Last edited by GMATPrepNow on 15 Apr 2018, 15:22, edited 1 time in total. CEO Joined: 11 Sep 2015 Posts: 3331 Location: Canada Re: Last year, Christine received 12 monthly paychecks. Each of the first [#permalink] ### Show Tags 27 Mar 2017, 07:25 Top Contributor 1 Bunuel wrote: Last year, Christine received 12 monthly paychecks. Each of the first four months’ paychecks was for$4500, and each of the remaining months’ paychecks was for $4800. What was her average paycheck for the year? A.$4600
B. $4650 C.$4700
D. $4750 E.$4800

Another approach is to use weighted averages.

Weighted average of groups combined = (group A proportion)(group A average) + (group B proportion)(group B average) + (group C proportion)(group C average) + ...

In this question, the proportion of $4500 paychecks = 4/12 = 1/3 And the proportion of$4800 paychecks = 8/12 = 2/3

Plugging these values into the formula, we get: average paycheck = (1/3)($4500) + (2/3)($4800)
= $1500 +$3200
= $4700 RELATED VIDEO _________________ Test confidently with gmatprepnow.com Board of Directors Status: QA & VA Forum Moderator Joined: 11 Jun 2011 Posts: 4330 Location: India GPA: 3.5 WE: Business Development (Commercial Banking) Re: Last year, Christine received 12 monthly paychecks. Each of the first [#permalink] ### Show Tags 27 Mar 2017, 10:01 Bunuel wrote: Last year, Christine received 12 monthly paychecks. Each of the first four months’ paychecks was for$4500, and each of the remaining months’ paychecks was for $4800. What was her average paycheck for the year? A.$4600
B. $4650 C.$4700
D. $4750 E.$4800

$$Average = \frac{4500*4 + 8*4800}{12}$$

$$Average = \frac{100*4 (45 + 2*48)}{12}$$

$$Average = \frac{100*(45 + 2*48)}{3}$$

$$Average = \frac{100*141}{3}$$

$$Average = 100*47$$

Thus, average must be $4700, correct answer must be (C)$4700
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Abhishek....

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Manager
Joined: 06 Dec 2016
Posts: 248
Re: Last year, Christine received 12 monthly paychecks. Each of the first  [#permalink]

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27 Mar 2017, 12:12
This one is ridiculously easy

4(4500) + 8(4800)/12
(18000 + 38400)/12
56400/12
4700

Target Test Prep Representative
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2830
Re: Last year, Christine received 12 monthly paychecks. Each of the first  [#permalink]

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17 Apr 2018, 15:28
Bunuel wrote:
Last year, Christine received 12 monthly paychecks. Each of the first four months’ paychecks was for $4500, and each of the remaining months’ paychecks was for$4800. What was her average paycheck for the year?

A. $4600 B.$4650
C. $4700 D.$4750
E. \$4800

We can create a weighted average equation:

(4 x 4500 + 8 x 4800)/12 = (18,000 + 38,400)/12 = 4,700

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Jeffery Miller

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Re: Last year, Christine received 12 monthly paychecks. Each of the first &nbs [#permalink] 17 Apr 2018, 15:28
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