amitjash
Let each different arrangement of all the letters of DELETED be called a word. In how many of these words will the D's be separated?
I am getting answer as 300. Can someone please explain if the answer is correct? I am not sure if wee need to carry out some operation because of repetation of D's.
There are 7 letters in the word "DELETED", out of which: D=2, E=3, L=1, T=1.
Total # of permutations is \(\frac{7!}{2!3!}=420\);
# of permutations with D's together is \(\frac{6!}{3!}=120\). Consider 2 D's as one unit: {DD}{E}{E}{E}{L}{T} - total 6 units, out of which {DD}=1, {E}=3, {L}=1, {T}=1.
# of permutations with D's
not come together is: \(\frac{7!}{2!3!}-\frac{6!}{3!}=300\).
So your answer is correct.
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