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Let x, y, and z be positive integers such that y is a multiple of x.

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Joined: 02 Sep 2009
Posts: 58310
Let x, y, and z be positive integers such that y is a multiple of x.  [#permalink]

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New post 10 Dec 2016, 06:29
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

74% (01:26) correct 26% (01:47) wrong based on 80 sessions

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Joined: 12 Aug 2015
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Schools: Boston U '20 (M)
GRE 1: Q169 V154
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Re: Let x, y, and z be positive integers such that y is a multiple of x.  [#permalink]

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New post 10 Dec 2016, 08:52
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1
Here is my solution to this one.
Given that y is a multiple of x=> y=kx
We need to check if y+z is a multiple of x.
Since y is already a multiple of x => y+z will be a multiple of x only if z is a multiple of x.
Else it wont be.

RULE -> Multiple +Multiple = Multiple
Multiple +Non Multiple = Non Multiple



Statement 1-->
Z=yk'=> xk*k'
Hence z is a multiple of x
Hence y+z will be multiple of x
Hence sufficient

Statement 2-->
No clue of z
Hence not sufficient

Hence A

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Re: Let x, y, and z be positive integers such that y is a multiple of x.  [#permalink]

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New post 10 Apr 2019, 23:31
As per statement 1:\(z=yb\)
that implies \(y+yb=xm\)
that implies \(y(1+b)=xm\),
hence \(y+z=xm\).
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Re: Let x, y, and z be positive integers such that y is a multiple of x.   [#permalink] 10 Apr 2019, 23:31
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Let x, y, and z be positive integers such that y is a multiple of x.

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