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Math Expert
Joined: 02 Sep 2009
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VP
VP
Joined: 20 Jul 2017
Posts: 1300
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Location: India
Concentration: Entrepreneurship, Marketing
GMAT 1: 690 Q51 V30
WE:Education (Education)
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Joined: 03 Jun 2019
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GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
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Joined: 04 Jan 2015
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Re: Let x1, x2, x3......xn be a sequence of positive numbers where X1 = 1, [#permalink]
Expert Reply

Solution


Given:
    • \(x_1, x_2, x_3,…., x_n\) is a sequence of positive numbers
    • \(x_1 = 1\)
    • \(x_{n+1} = x_n + 4\)

To find:
    • The \(n^{th}\) term of the sequence

Approach and Working Out:
    • Given,\(x_{n+1} = x_n + 4\)
      o Implies,\(x_{n+1} - x_n = 4\)
      o Thus, we can say that all the terms of the sequence are in AP

    • \(t_n = a + (n – 1) * d\), where \(a = x_1\) and d = 4

Therefore, the nth term = 1 + (n – 1) * 4 = 4n - 3

Hence, the correct answer is Option C.

Answer: C
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Re: Let x1, x2, x3......xn be a sequence of positive numbers where X1 = 1, [#permalink]
How would you solve this if you didn't memorize the Arithmetic Progression formula?
GMAT Club Bot
Re: Let x1, x2, x3......xn be a sequence of positive numbers where X1 = 1, [#permalink]
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