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# Let x1, x2, x3......xn be a sequence of positive numbers where X1 = 1,

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Math Expert
Joined: 02 Sep 2009
Posts: 49271
Let x1, x2, x3......xn be a sequence of positive numbers where X1 = 1,  [#permalink]

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03 Jul 2018, 09:52
00:00

Difficulty:

35% (medium)

Question Stats:

71% (01:19) correct 29% (02:58) wrong based on 28 sessions

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Let $$x_1$$, $$x_2$$, $$x_3$$, ..., $$x_n$$ be a sequence of positive numbers where $$x_1 = 1$$, and $$x_{n+1} = x_n + 4$$. What represents the $$n_{th}$$ term in the sequence?

A. -3n

B. 3n - 4

C. 4n - 3

D. 4n - 4

E. 5n

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Re: Let x1, x2, x3......xn be a sequence of positive numbers where X1 = 1,  [#permalink]

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03 Jul 2018, 09:58
Substitute n = 1 in options. Only Option C works.
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Joined: 14 Jun 2018
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Re: Let x1, x2, x3......xn be a sequence of positive numbers where X1 = 1,  [#permalink]

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03 Jul 2018, 10:26
1st term is 1 , 2nd is 5 , 3rd is 9...series with difference 4.
a+(n-1)d = 1 + (n-1)4 = 4n-3
Manager
Joined: 01 Feb 2017
Posts: 155
Re: Let x1, x2, x3......xn be a sequence of positive numbers where X1 = 1,  [#permalink]

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05 Jul 2018, 03:20
X1 = 1
X2 = X1 + 4 = 5= 1 + 4(2-1)
X3 = X2 + 4 = 9= 1 + 4(3-1)
X4 = X3 + 4 =13= 1 + 4(4-1)
Xn = 1 + 4(n-1) = 4n - 3

Hence, Ans C

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Re: Let x1, x2, x3......xn be a sequence of positive numbers where X1 = 1, &nbs [#permalink] 05 Jul 2018, 03:20
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