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27 Jan 2007, 23:21
Kudos
Bookmarks
Lines N and P lie on the XY plane, is the slope of the line N less than the slope of the line P?
1. Lines N and P intersect at point (5,1)
2. Y intercept of line N is greater than y intercept of line P
Answer C. (Together sufficient).
Solution please? Thanks!
1. Lines N and P intersect at point (5,1)
2. Y intercept of line N is greater than y intercept of line P
Answer C. (Together sufficient).
Solution please? Thanks!
Archived Topic
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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28 Jan 2007, 02:11
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(C) it is 
Reasonning approach
To know the slope of a line, we need at least 2 points that are known to be on the line.
Stat1
The 2 lines pass by the same point (5,1). We cannot conclude on their respective slopes, so we cannot conclude on a relationship between the 2 slopes.
INSUFF.
Stat2
The 2 lines pass by 2 different points (5,1). Once again, we cannot conclude on a relationship between the 2 slopes.
INSUFF.
Both (1) and (2)
We don't want to know directly the values of slopes but only if one is above the other one.
Since we know that the 2 lines passes by the same point and that,to arrive at this point, these 2 lines are passing by 2 different points known to be one above the other one, we have 3 major cases:
> N "decelerates" faster than P does
> N "decelerates" faster than P "increases"
> P "increases" faster than P "decelerates"
Thus, slope(P) > slope(N)
SUFF.
Algebric approach
We have:
o y = a(n) * x + b(n)
o y = a(p) * x + b(p)
Stat1
Both lines passes by (5,1) implies that,
o 1 = 5*a(n) + b(n)
and
1 = 5*a(p) + b(p)
=> 5*a(n) + b(n) = 5*a(p) + b(p)
we need another relationship to conclude.
INSUFF.
Stat2
b(p) > b(n)
No ideas about a(n) and a(p).
INSUFF.
Both (1) and (2)
Since 1 = 5*a(n) + b(n), then b(n) = 1 - 5*a(n)
Similarly, b(p) = 1 - 5*a(p)
Then, as b(p) > b(n), we have :
1 - 5*a(n) > 1 - 5*a(p)
=> a(p) > a(n)
SUFF.
Reasonning approach
To know the slope of a line, we need at least 2 points that are known to be on the line.
Stat1
The 2 lines pass by the same point (5,1). We cannot conclude on their respective slopes, so we cannot conclude on a relationship between the 2 slopes.
INSUFF.
Stat2
The 2 lines pass by 2 different points (5,1). Once again, we cannot conclude on a relationship between the 2 slopes.
INSUFF.
Both (1) and (2)
We don't want to know directly the values of slopes but only if one is above the other one.
Since we know that the 2 lines passes by the same point and that,to arrive at this point, these 2 lines are passing by 2 different points known to be one above the other one, we have 3 major cases:
> N "decelerates" faster than P does
> N "decelerates" faster than P "increases"
> P "increases" faster than P "decelerates"
Thus, slope(P) > slope(N)
SUFF.
Algebric approach
We have:
o y = a(n) * x + b(n)
o y = a(p) * x + b(p)
Stat1
Both lines passes by (5,1) implies that,
o 1 = 5*a(n) + b(n)
and
1 = 5*a(p) + b(p)
=> 5*a(n) + b(n) = 5*a(p) + b(p)
we need another relationship to conclude.
INSUFF.
Stat2
b(p) > b(n)
No ideas about a(n) and a(p).
INSUFF.
Both (1) and (2)
Since 1 = 5*a(n) + b(n), then b(n) = 1 - 5*a(n)
Similarly, b(p) = 1 - 5*a(p)
Then, as b(p) > b(n), we have :
1 - 5*a(n) > 1 - 5*a(p)
=> a(p) > a(n)
SUFF.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
