gmatdelhi
Official Explanation:
Statement (1) by itself is sufficient. All the variables equal zero, and the product of the variables is zero; therefore their product is even.My issue here is: is 0 an even number? I thought it was neither even nor odd. I've made flashcards where I put in this statement, but I don't remember the source. So I'm confused about 0 now. Help?! Statement (2) by itself is insufficient. The variables can be either odd or even. If all the variables are even, their product is even; if they are odd, their product is odd.
The correct answer is A.
Zero is an even integer. An even number is an
integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder.
An even number is an
integer of the form \(n=2k\), where \(k\) is an integer.
So for \(k=0\) --> \(n=2*0=0\).
For more on number properties check:
math-number-theory-88376.htmlAs for the question:
Is the product abcd even?(1) a^2+b^2+c^2+d^2=0 --> number squared is always non-negative (zero or positive), so the sum of 4 non-negative values to be 0 then each must be zero, so abcd=0=even. Sufficient.
(2) a=b=c=d. Clearly insufficient.
Answer: A.
Hope it's clear.