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M02-14

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M02-14 [#permalink]

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New post 16 Sep 2014, 00:17
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A
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C
D
E

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78% (00:49) correct 22% (00:45) wrong based on 149 sessions

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New post 16 Sep 2014, 00:17
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Official Solution:

\(xy^2+ yx^2 = xy(x+y)\)

Statement (1) by itself is insufficient. We know that \(xy=6\), but we do not know what \(x+y\) equals.

Statement (2) by itself is insufficient. We know that \(x\) is a prime number, but there is no information about \(y\).

Statements (1) and (2) combined are sufficient. If \(xy=6\), then the possible values of \(x\) and \(y\) are either 1 and 6 or 2 and 3. If \(x\) is a prime number and \(x \gt y\), then \(x=3\) and \(y=2\).


Answer: C
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Re: M02-14 [#permalink]

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New post 23 Sep 2014, 09:47
I'm unclear as to why Statement (1) is insufficient...


Factoring the provided equation leaves us with xy(x+y). As such, we need to figure out what "xy" is equal to, and what "(x+y)" is equal to.

Statement (1) tells us that xy=6. Hence, possibilities: x=2 and y=3, x=3 and y=2, or their negative counterparts. HOWEVER, we are also told by the prompt that both x and y are positive integers, and that x >y. Thus, x MUST be 3 and y MUST be 2. This provides us with sufficient information.

What am I missing?

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New post 23 Sep 2014, 09:57
bartone89 wrote:
I'm unclear as to why Statement (1) is insufficient...


Factoring the provided equation leaves us with xy(x+y). As such, we need to figure out what "xy" is equal to, and what "(x+y)" is equal to.

Statement (1) tells us that xy=6. Hence, possibilities: x=2 and y=3, x=3 and y=2, or their negative counterparts. HOWEVER, we are also told by the prompt that both x and y are positive integers, and that x >y. Thus, x MUST be 3 and y MUST be 2. This provides us with sufficient information.

What am I missing?


What about a case when x = 6 and y = 1 ?
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Re: M02-14 [#permalink]

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New post 01 Apr 2015, 07:04
What if x=1 and y=6? Please explain.

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Re: M02-14 [#permalink]

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New post 25 Sep 2017, 18:54
Given that xy = 6, why can't we just plug 6 in for both (xy)^2 and (yx)^2 to get 6^2+6^2 for Statement 1?

Thanks!

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New post 25 Sep 2017, 20:47
Gmatfrog3 wrote:
Given that xy = 6, why can't we just plug 6 in for both (xy)^2 and (yx)^2 to get 6^2+6^2 for Statement 1?

Thanks!


Because it's not (xy)^2 + (yx)^2 but x*y^2 + y*x^2. If it were (xy)^2 + (yx)^2 it would have been written that way (in brackets), without them xy^2 ALWAYS means x*y^2.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
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Kudos [?]: 128512 [0], given: 12179

Re: M02-14   [#permalink] 25 Sep 2017, 20:47
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