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M02-29

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M02-29 [#permalink]

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New post 15 Sep 2014, 23:18
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New post 15 Sep 2014, 23:18
Official Solution:


Is \(x=x^2\)?

Is \(x(x-1)=0\)? So, the question basically asks whether \(x=0\) or \(x=1\).

(1) \(x \ne 0\). If \(x=1\) then the answer is YES but if \(x\) is any other number (except zero, which is ruled out) then the answer is NO. Not sufficient.

(2) \(x \gt 1\). Both options (\(x=0\) or \(x=1\)) are ruled out hence we know that \(x \ne x^2\). Sufficient.


Answer: B
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M02-29 [#permalink]

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New post 22 Apr 2015, 07:22
It is B - option one says nothing, just says not 0 so it could be 1 or anything else. 0^2 or 1^2 are x=x^2 , but the second option confirms that x =/= x^2. so B is sufficient.

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New post 14 Oct 2017, 03:19
hi should the answer to this ques not be e.?

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Re: M02-29   [#permalink] 14 Oct 2017, 03:22
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