GMAT Changed on April 16th - Read about the latest changes here

 It is currently 24 May 2018, 18:37

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# M02-36

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 45367
M02-36 [#permalink]

### Show Tags

16 Sep 2014, 00:19
Expert's post
6
This post was
BOOKMARKED
00:00

Difficulty:

45% (medium)

Question Stats:

54% (00:47) correct 46% (01:01) wrong based on 205 sessions

### HideShow timer Statistics

If $$x$$ is an integer, what is the value of $$x$$?

(1) $$x^2 = x^3$$

(2) $$x$$ is both a perfect square and a perfect cube. (Note: a perfect square, is an integer that can be written as the square of an integer. For example $$16=4^2$$, is a perfect square. Similarly a perfect cube, is an integer that can be written as the cube of an integer. For example $$27=3^3$$, is a perfect cube.)

_________________
Math Expert
Joined: 02 Sep 2009
Posts: 45367
Re M02-36 [#permalink]

### Show Tags

16 Sep 2014, 00:19
Official Solution:

Statement (1) by itself is insufficient. $$x$$ can be 0 or 1.

Statement (2) by itself is insufficient. Perfect squares are integers 0, 1, 4, 9, 16, and so on. Similarly, perfect cubes are: 0, 1, 8, 27, 64... Thus $$x$$ can be 0 or 1.

Statements (1) and (2) combined are insufficient. For example: $$x$$ can still be 0 or 1.

Answer: E
_________________
Director
Joined: 05 Sep 2010
Posts: 785
Re: M02-36 [#permalink]

### Show Tags

07 Nov 2014, 11:02
the hint in the question seems misleading especially when it is read very literally

hint says: Similarly a perfect cube, is an integer that can be written as the cube of some other integer-----------> this implies that 1 cannot be a perfect cube because 1 cannot be written as a cube of "some other integer" but yes it can be written as a cube of 1 itself !! , according to this hint numbers like 125 ( for 125 can be written as 5^3 ---->other integer 5 ) will fall into this definition .
however , if one does not look at the hint then it is oki because as per common knowledge 1 does qualify as perfect cube
Manager
Joined: 18 Jul 2013
Posts: 69
Location: Italy
GMAT 1: 600 Q42 V31
GMAT 2: 700 Q48 V38
Re: M02-36 [#permalink]

### Show Tags

27 Dec 2014, 05:27
aditya8062 wrote:
the hint in the question seems misleading especially when it is read very literally

hint says: Similarly a perfect cube, is an integer that can be written as the cube of some other integer-----------> this implies that 1 cannot be a perfect cube because 1 cannot be written as a cube of "some other integer" but yes it can be written as a cube of 1 itself !! , according to this hint numbers like 125 ( for 125 can be written as 5^3 ---->other integer 5 ) will fall into this definition .
however , if one does not look at the hint then it is oki because as per common knowledge 1 does qualify as perfect cube

i agree with you,
this definition confused me
Intern
Joined: 09 Mar 2013
Posts: 18
Location: Russian Federation
Concentration: General Management, Entrepreneurship
GMAT 1: 550 Q43 V23
GMAT 2: 590 Q49 V22
GMAT 3: 690 Q49 V34
GMAT 4: 740 Q49 V41
Re: M02-36 [#permalink]

### Show Tags

29 Apr 2015, 18:12
It's a quite controversial problem.
Hope I won't face similar one on the GMAT.

http://mathforum.org/library/drmath/view/52368.html
http://www.ask.com/math/zero-perfect-sq ... 33a2cfecf1
Manager
Joined: 31 Jul 2014
Posts: 138
GMAT 1: 630 Q48 V29
Re: M02-36 [#permalink]

### Show Tags

24 Sep 2015, 12:19
Bunuel wrote:
Official Solution:

Statement (1) by itself is insufficient. $$x$$ can be 0 or 1.

Statement (2) by itself is insufficient. Perfect squares are integers 0, 1, 4, 9, 16, and so on. Similarly, perfect cubes are: 0, 1, 8, 27, 64... Thus $$x$$ can be 0 or 1.

Statements (1) and (2) combined are insufficient. For example: $$x$$ can still be 0 or 1.

Answer: E

I think for stmnt 2) 0,1,64,729 are there but i ignored 0 and 1 becoz u said cube and square of "other" number
Current Student
Joined: 29 Apr 2014
Posts: 123
Location: Viet Nam
Concentration: Finance, Technology
GMAT 1: 640 Q50 V26
GMAT 2: 660 Q51 V27
GMAT 3: 680 Q50 V31
GMAT 4: 710 Q50 V35
GMAT 5: 760 Q50 V42
Re: M02-36 [#permalink]

### Show Tags

17 Nov 2015, 16:37
I agree. The hint in (2) is really confusing. However, I don't know why I thought 1, but not 0, satisfy this condition and thus chose B as the correct answer .
Current Student
Joined: 03 May 2015
Posts: 11
Re: M02-36 [#permalink]

### Show Tags

14 Dec 2015, 04:39
1
This post was
BOOKMARKED
I think this is a high-quality question and I agree with explanation. Please change the definition containing "of some other integer" to " of any integer" ; then the question is right; else 0 and 1 cannot be answers to option 2, thanks.
Math Expert
Joined: 02 Sep 2009
Posts: 45367
Re: M02-36 [#permalink]

### Show Tags

19 Jan 2016, 10:43
joyandbliss wrote:
I think this is a high-quality question and I agree with explanation. Please change the definition containing "of some other integer" to " of any integer" ; then the question is right; else 0 and 1 cannot be answers to option 2, thanks.

Updated the question.
_________________
Intern
Joined: 07 Feb 2018
Posts: 4
M02-36 [#permalink]

### Show Tags

Updated on: 13 May 2018, 11:42
NOTE THIS PLEASE ... the question clearly states that x is an INTEGER so x^2 = x^3 should be sufficient as 0 does not qualify as an integer and x can only take the value 1.THE question starts as if x is an INTEGER.
give me kudos if you think iam right:)

Originally posted by Vibhav10 on 13 May 2018, 11:35.
Last edited by Vibhav10 on 13 May 2018, 11:42, edited 1 time in total.
Intern
Joined: 07 Feb 2018
Posts: 4
M02-36 [#permalink]

### Show Tags

13 May 2018, 11:40
Bunuel wrote:
Official Solution:

Statement (1) by itself is insufficient. $$x$$ can be 0 or 1.

Statement (2) by itself is insufficient. Perfect squares are integers 0, 1, 4, 9, 16, and so on. Similarly, perfect cubes are: 0, 1, 8, 27, 64... Thus $$x$$ can be 0 or 1.

Statements (1) and (2) combined are insufficient. For example: $$x$$ can still be 0 or 1.

Answer: E

NOTE THIS PLEASE ... the question clearly states that x is an INTEGER so x^2 = x^3 should be sufficient as 0 does not qualify as an integer and x can only take the value 1.THE question starts as if x is an INTEGER. i may be wrong somewhere though.
give me kudos if you think iam right:)
Math Expert
Joined: 02 Sep 2009
Posts: 45367
Re: M02-36 [#permalink]

### Show Tags

13 May 2018, 12:36
Vibhav10 wrote:
Bunuel wrote:
Official Solution:

Statement (1) by itself is insufficient. $$x$$ can be 0 or 1.

Statement (2) by itself is insufficient. Perfect squares are integers 0, 1, 4, 9, 16, and so on. Similarly, perfect cubes are: 0, 1, 8, 27, 64... Thus $$x$$ can be 0 or 1.

Statements (1) and (2) combined are insufficient. For example: $$x$$ can still be 0 or 1.

Answer: E

NOTE THIS PLEASE ... the question clearly states that x is an INTEGER so x^2 = x^3 should be sufficient as 0 does not qualify as an integer and x can only take the value 1.THE question starts as if x is an INTEGER. i may be wrong somewhere though.
give me kudos if you think iam right:)

That's wrong.

ZERO:

1. 0 is an integer.

2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even.

3. 0 is neither positive nor negative integer (the only one of this kind).

4. 0 is divisible by EVERY integer except 0 itself.

You should brush-up fundamentals before practising questions:
ALL YOU NEED FOR QUANT ! ! !
Ultimate GMAT Quantitative Megathread

Hope it helps.
_________________
Re: M02-36   [#permalink] 13 May 2018, 12:36
Display posts from previous: Sort by

# M02-36

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

Moderators: chetan2u, Bunuel

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.