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Question Stats:
59% (00:59) correct 41% (01:17) wrong based on 256 sessions
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If \(x\) is an integer, what is the value of \(x\)? (1) \(x^2 = x^3\) (2) \(x\) is both a perfect square and a perfect cube. (Note: a perfect square, is an integer that can be written as the square of an integer. For example \(16=4^2\), is a perfect square. Similarly a perfect cube, is an integer that can be written as the cube of an integer. For example \(27=3^3\), is a perfect cube.)
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16 Sep 2014, 00:19
Official Solution: Statement (1) by itself is insufficient. \(x\) can be 0 or 1. Statement (2) by itself is insufficient. Perfect squares are integers 0, 1, 4, 9, 16, and so on. Similarly, perfect cubes are: 0, 1, 8, 27, 64... Thus \(x\) can be 0 or 1. Statements (1) and (2) combined are insufficient. For example: \(x\) can still be 0 or 1. Answer: E
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Re: M0236
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07 Nov 2014, 11:02
the hint in the question seems misleading especially when it is read very literally
hint says: Similarly a perfect cube, is an integer that can be written as the cube of some other integer> this implies that 1 cannot be a perfect cube because 1 cannot be written as a cube of "some other integer" but yes it can be written as a cube of 1 itself !! , according to this hint numbers like 125 ( for 125 can be written as 5^3 >other integer 5 ) will fall into this definition . however , if one does not look at the hint then it is oki because as per common knowledge 1 does qualify as perfect cube



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Re: M0236
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27 Dec 2014, 05:27
aditya8062 wrote: the hint in the question seems misleading especially when it is read very literally
hint says: Similarly a perfect cube, is an integer that can be written as the cube of some other integer> this implies that 1 cannot be a perfect cube because 1 cannot be written as a cube of "some other integer" but yes it can be written as a cube of 1 itself !! , according to this hint numbers like 125 ( for 125 can be written as 5^3 >other integer 5 ) will fall into this definition . however , if one does not look at the hint then it is oki because as per common knowledge 1 does qualify as perfect cube i agree with you, this definition confused me



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Re: M0236
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Re: M0236
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24 Sep 2015, 12:19
Bunuel wrote: Official Solution:
Statement (1) by itself is insufficient. \(x\) can be 0 or 1. Statement (2) by itself is insufficient. Perfect squares are integers 0, 1, 4, 9, 16, and so on. Similarly, perfect cubes are: 0, 1, 8, 27, 64... Thus \(x\) can be 0 or 1. Statements (1) and (2) combined are insufficient. For example: \(x\) can still be 0 or 1.
Answer: E I think for stmnt 2) 0,1,64,729 are there but i ignored 0 and 1 becoz u said cube and square of "other" number



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Re: M0236
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17 Nov 2015, 16:37
I agree. The hint in (2) is really confusing. However, I don't know why I thought 1, but not 0, satisfy this condition and thus chose B as the correct answer .



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Re: M0236
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14 Dec 2015, 04:39
I think this is a highquality question and I agree with explanation. Please change the definition containing "of some other integer" to " of any integer" ; then the question is right; else 0 and 1 cannot be answers to option 2, thanks.



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Re: M0236
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19 Jan 2016, 10:43
joyandbliss wrote: I think this is a highquality question and I agree with explanation. Please change the definition containing "of some other integer" to " of any integer" ; then the question is right; else 0 and 1 cannot be answers to option 2, thanks. Updated the question.
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M0236
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Updated on: 13 May 2018, 11:42
NOTE THIS PLEASE ... the question clearly states that x is an INTEGER so x^2 = x^3 should be sufficient as 0 does not qualify as an integer and x can only take the value 1.THE question starts as if x is an INTEGER. give me kudos if you think iam right:)
Originally posted by Vibhav10 on 13 May 2018, 11:35.
Last edited by Vibhav10 on 13 May 2018, 11:42, edited 1 time in total.



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Bunuel wrote: Official Solution:
Statement (1) by itself is insufficient. \(x\) can be 0 or 1. Statement (2) by itself is insufficient. Perfect squares are integers 0, 1, 4, 9, 16, and so on. Similarly, perfect cubes are: 0, 1, 8, 27, 64... Thus \(x\) can be 0 or 1. Statements (1) and (2) combined are insufficient. For example: \(x\) can still be 0 or 1.
Answer: E NOTE THIS PLEASE ... the question clearly states that x is an INTEGER so x^2 = x^3 should be sufficient as 0 does not qualify as an integer and x can only take the value 1.THE question starts as if x is an INTEGER. i may be wrong somewhere though. give me kudos if you think iam right:)



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Re: M0236
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13 May 2018, 12:36
Vibhav10 wrote: Bunuel wrote: Official Solution:
Statement (1) by itself is insufficient. \(x\) can be 0 or 1. Statement (2) by itself is insufficient. Perfect squares are integers 0, 1, 4, 9, 16, and so on. Similarly, perfect cubes are: 0, 1, 8, 27, 64... Thus \(x\) can be 0 or 1. Statements (1) and (2) combined are insufficient. For example: \(x\) can still be 0 or 1.
Answer: E NOTE THIS PLEASE ... the question clearly states that x is an INTEGER so x^2 = x^3 should be sufficient as 0 does not qualify as an integer and x can only take the value 1.THE question starts as if x is an INTEGER. i may be wrong somewhere though. give me kudos if you think iam right:) That's wrong. ZERO:1. 0 is an integer.2. 0 is an even integer. An even number is an integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even. 3. 0 is neither positive nor negative integer (the only one of this kind). 4. 0 is divisible by EVERY integer except 0 itself. You should brushup fundamentals before practising questions: ALL YOU NEED FOR QUANT ! ! !Ultimate GMAT Quantitative MegathreadHope it helps.
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Re: M0236
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15 Nov 2018, 22:55
totally unfair i thought about 0 ...then the number has to be a perfect square , cube ...i figured 0 should not be counted ((((((((((



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Re M0236
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17 Feb 2019, 20:02
Hi! just wanted to know what is 0*0?
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Re: M0236
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17 Feb 2019, 20:41
patto wrote: Hi! just wanted to know what is 0*0? patto It is indeed 0. Even \(0^3\) = 0 It is part of the perfect squares
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