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# M04-03

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Math Expert
Joined: 02 Sep 2009
Posts: 49303

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16 Sep 2014, 00:22
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Difficulty:

5% (low)

Question Stats:

87% (00:47) correct 13% (00:47) wrong based on 153 sessions

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If $$m$$ and $$n$$ are consecutive positive integers, is $$m$$ greater than $$n$$?

(1) $$m-1$$ and $$n+1$$ are consecutive positive integers

(2) $$m$$ is an even integer

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16 Sep 2014, 00:22
1
Official Solution:

(1) $$m-1$$ and $$n+1$$ are consecutive positive integers. If $$m$$ were less than $$n$$ than $$m-1$$ (integer less than $$m$$) and $$n+1$$ (integer more than $$n$$) wouldn't be consecutive, so $$m$$ is greater than $$n$$. Sufficient.

Or look at this in another way: stem says that the distance between m and n is 1. Now, if $$m \lt n$$ then the distance between $$m-1$$ and $$n+1$$ would be 3 and they couldn't be consecutive as (1) states. Thus it must be true that $$m \gt n$$.

(2) $$m$$ is an even integer. Clearly insufficient.

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Joined: 06 Sep 2013
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WE: Analyst (Investment Banking)

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31 Jan 2015, 12:35
I think this question is good and helpful.
Hi,
M an N are consecutive positive integers (like 5 and 6).
But could be 6 and 5 consecutive positive intergers?
Thanks,
Mike
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01 Feb 2015, 04:44
Mikeruz wrote:
I think this question is good and helpful.
Hi,
M an N are consecutive positive integers (like 5 and 6).
But could be 6 and 5 consecutive positive intergers?
Thanks,
Mike

The order there does not matter: 5 and 6, or 6 and 5, are consecutive integers.
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Joined: 07 Feb 2015
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24 Jun 2015, 15:57
I looked at this in the following way. I first grouped n and n+1 in a consecutive manner. Since n is positive, n+1 cannot come before n. Thus, n listed consecutively is:
n, n+1

M is similar. Since m is positive, the grouping cannot be m, m-1. So it must be:
m-1, m

Thus, since n+1 and m-1 are consecutive, the consecutive grouping must be n, n+1, m-1, m, meaning that m is always greater than m, which means (1) is sufficient.

(2) This cannot be sufficient because n is not mentioned.

I liked doing it this way, but I don't know if this would be Bunuel approved.
Intern
Joined: 02 Jan 2018
Posts: 27
GMAT 1: 730 Q49 V40

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05 Jul 2018, 07:12
Easiest way is to give m+1 and n-1 consecutive values. Two scenarios:

1. m>n (e.g. m=3,n=2)
2. n>m (e.g. n=3, m=2)

You'll notice that when you solve both both (1) and (2) the answer is the same.
Re: M04-03 &nbs [#permalink] 05 Jul 2018, 07:12
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# M04-03

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