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M04-23

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M04-23  [#permalink]

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New post 15 Sep 2014, 23:23
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

79% (00:28) correct 21% (00:17) wrong based on 163 sessions

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Re M04-23  [#permalink]

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New post 15 Sep 2014, 23:23
1
Official Solution:


(1) \(\frac{z}{3}\) is odd. Given: \(\frac{z}{3}=odd\), so \(z=3*\text{odd}=\text{odd}\). Sufficient.

(2) \(3z\) is odd. Given: \(3z=\text{odd}\). In order the product of two integers 3 and \(z\) to be odd both must be odd. So, \(z=\text{odd}\). Sufficient.


Answer: D
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Re M04-23  [#permalink]

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New post 27 Aug 2015, 09:34
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I think this is a poor-quality question and I don't agree with the explanation. when z=6 in first statment, z/3 odd, but z is even na. how it is sufficient?
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M04-23  [#permalink]

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New post Updated on: 10 Jan 2019, 02:07
What about 3 (1/3)=1

Originally posted by wali786 on 10 Jan 2019, 01:28.
Last edited by wali786 on 10 Jan 2019, 02:07, edited 1 time in total.
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New post 10 Jan 2019, 01:41
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Re: M04-23  [#permalink]

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New post 10 Jan 2019, 02:06
Is integer zz odd?
(1) z3 is odd

(2) 3z is odd

Second Statement says 3z is odd. According to statement 2, z could (1/3) then 3z=1, which is still odd.
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New post 10 Jan 2019, 02:11
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Re: M04-23  [#permalink]

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New post 10 Jan 2019, 06:01
Bunuel wrote:
Is integer \(z\) odd?


(1) \(\frac{z}{3}\) is odd

(2) \(3z\) is odd


#1 :
z has to be odd sufficeint

#2 :
3z : will give odd integer when z is odd
sufficient

IMOD
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Re: M04-23 &nbs [#permalink] 10 Jan 2019, 06:01
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