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16 Sep 2014, 00:25
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What is the value of \(x\)?
(1) \(x^2 - 12x + 32 = 0\)
(2) \(x \ge 0\)
(1) \(x^2 - 12x + 32 = 0\)
(2) \(x \ge 0\)
16 Sep 2014, 00:25
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Official Solution:
What is the value of \(x\)?
(1) \(x^2 - 12x + 32 = 0\)
Factoring the given quadratic, we get \((x - 4)(x - 8) = 0\). Thus, \(x\) could be either 4 or 8. Not sufficient.
(2) \(x \ge 0\)
This only tells us that \(x\) is non-negative. On its own, this is not sufficient to determine the value of \(x\).
(1)+(2) Both possible values of \(x\) from (1) are positive, so \(x\) could still be either 4 or 8. Not sufficient.
Answer: E
What is the value of \(x\)?
(1) \(x^2 - 12x + 32 = 0\)
Factoring the given quadratic, we get \((x - 4)(x - 8) = 0\). Thus, \(x\) could be either 4 or 8. Not sufficient.
(2) \(x \ge 0\)
This only tells us that \(x\) is non-negative. On its own, this is not sufficient to determine the value of \(x\).
(1)+(2) Both possible values of \(x\) from (1) are positive, so \(x\) could still be either 4 or 8. Not sufficient.
Answer: E
