If a company sells \(S\) tons (1 ton = 1000 kilograms) of product A annually and charges \(B\) dollars per ton, what is the profit if it costs \(G\) dollars to manufacture a kilogram of product A and \(P\) dollars to ship it to the customer?

(A) \(b-1000g+1000p\)

(B) \(bs-\frac{g+p}{1000}\)

(C) \((b-(g+p))*s\)

(D) \(\left(\frac{g}{1000}-(b+p)\right)*s\)

(E) \(\left(\frac{b}{1000}-(g+p)\right)*1000s\)

Source: GMAT Club Tests - hardest GMAT questions

My Question: I believe this solution is wrong. The final answer has units of $/kg inside the parenthesis, multiplied by S which is in tons. If somebody sees something I don't, let me know. Also, the explanation is confusing since they say use $5/kg as B, but then divide B by 1000 in the final equation (which converts /ton to /kg). Another thing is the question doesn't say if the shipping cost is per ton or per kg. Overall, this is a confusing question, confusing enough to have a wrong answer, so should probably be thrown away or reworded.

A. $0

B. $2

C. $4

D. $6

E. $8

Let the markup be \($x\), so \(x\) must be 25% of the selling price, which would be \(120+x\): \(x=0.25(120+x)\) --> \(x=40\). Hence the selling price was \(120+40=160\).

The price after the discount of 20% would be \(160*0.8=128\) --> gross profit on the sale:

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