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# M09-22

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Intern
Joined: 09 Aug 2014
Posts: 8
M09-22  [#permalink]

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31 Aug 2017, 12:10
Bunuel wrote:
When $$x\leq{0}$$ then $$|x|=-x$$, or more generally when $$some \ expression\leq{0}$$ then $$|some \ expression|={-(some \ expression)}$$. For example: $$|-5|=5=-(-5)$$;
[/textarea]

Hi Bunuel,

I believe |x|=-x if x<0 and not if x≤0.

Please correct me if I am wrong.

Regards
Srinath
Math Expert
Joined: 02 Sep 2009
Posts: 52294
Re: M09-22  [#permalink]

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31 Aug 2017, 20:26
krsrinath wrote:
Bunuel wrote:
When $$x\leq{0}$$ then $$|x|=-x$$, or more generally when $$some \ expression\leq{0}$$ then $$|some \ expression|={-(some \ expression)}$$. For example: $$|-5|=5=-(-5)$$;
[/textarea]

Hi Bunuel,

I believe |x|=-x if x<0 and not if x≤0.

Please correct me if I am wrong.

Regards
Srinath

|0| = -0 = 0. So, what I've written is correct.
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Intern
Joined: 05 Feb 2017
Posts: 2
Re M09-22  [#permalink]

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25 Nov 2017, 02:36
I think this is a high-quality question and I agree with explanation. Brilliant
Intern
Joined: 11 Aug 2017
Posts: 5
WE: Account Management (Energy and Utilities)
Re: M09-22  [#permalink]

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06 Dec 2017, 22:02
I think i am missing something.

Can you explain why "A" can be eliminated? Isn't -0.5 less than than 1?

A. x>1. Not necessarily true since x could be -0.5;
Math Expert
Joined: 02 Sep 2009
Posts: 52294
Re: M09-22  [#permalink]

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06 Dec 2017, 22:14
DouglassJensen wrote:
I think i am missing something.

Can you explain why "A" can be eliminated? Isn't -0.5 less than than 1?

A. x>1. Not necessarily true since x could be -0.5;

We know that −1 < x < 0 or x > 1. The question asks to determine which of the options MUST be true.

A says: x > 1. This options is NOT always true because x could be from any number from −1 < x < 0, and if it is, then x > 1 won't be true. Please re-read the whole discussion again and follow the links provided there.

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Intern
Joined: 09 Apr 2018
Posts: 13
Re: M09-22  [#permalink]

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05 Jul 2018, 01:46
But B would fail for x = 1.
As it is a must be true case it will fail for x = 1 (where 1 > -1).
So B can not be the answer.
Math Expert
Joined: 02 Sep 2009
Posts: 52294
Re: M09-22  [#permalink]

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21 Jul 2018, 11:19
dpkgirdhar wrote:
I think this is a poor-quality question and I don't agree with the explanation. YOUR ANSWER IS INCORRECT. CHECK IT WHEN X=1

You did not understand the question and the solution. Also, it seems that you did not read the discussion. Please read the whole discussion before posting a question.

To understand the underline concept better practice other Trickiest Inequality Questions Type: Confusing Ranges.

P.S. ALL questions in the tests are correct.
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Joined: 18 Aug 2017
Posts: 1248
Location: India
Concentration: Sustainability, Marketing
WE: Marketing (Energy and Utilities)
Re: M09-22  [#permalink]

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10 Nov 2018, 07:57
If x≠0x≠0 and x|x|<xx|x|<x, which of the following must be true?

A. x>1x>1
B. x>−1x>−1
C. |x|<1|x|<1
D. |x|&gt;1
E. −1<x<0

From given stem, we need to plug in values in relation to given set of options, for which only option B is valid
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Intern
Joined: 12 Jan 2018
Posts: 15
Re M09-22  [#permalink]

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08 Jan 2019, 06:23
I think this is a high-quality question and I don't agree with the explanation. Correct answer must be E. Option B fails at X=0.5.
Math Expert
Joined: 02 Sep 2009
Posts: 52294
Re: M09-22  [#permalink]

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08 Jan 2019, 06:34
aarkay wrote:
I think this is a high-quality question and I don't agree with the explanation. Correct answer must be E. Option B fails at X=0.5.

Unfortunately you did not understand the question and the solution. Also, it seems that you did not read the discussion. Please read the whole discussion.

To understand the underline concept better practice other Trickiest Inequality Questions Type: Confusing Ranges.
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Re: M09-22 &nbs [#permalink] 08 Jan 2019, 06:34

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# M09-22

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