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# M09-22

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Intern
Joined: 09 Aug 2014
Posts: 8

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31 Aug 2017, 12:10
Bunuel wrote:
When $$x\leq{0}$$ then $$|x|=-x$$, or more generally when $$some \ expression\leq{0}$$ then $$|some \ expression|={-(some \ expression)}$$. For example: $$|-5|=5=-(-5)$$;
[/textarea]

Hi Bunuel,

I believe |x|=-x if x<0 and not if x≤0.

Please correct me if I am wrong.

Regards
Srinath
Math Expert
Joined: 02 Sep 2009
Posts: 50623

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31 Aug 2017, 20:26
krsrinath wrote:
Bunuel wrote:
When $$x\leq{0}$$ then $$|x|=-x$$, or more generally when $$some \ expression\leq{0}$$ then $$|some \ expression|={-(some \ expression)}$$. For example: $$|-5|=5=-(-5)$$;
[/textarea]

Hi Bunuel,

I believe |x|=-x if x<0 and not if x≤0.

Please correct me if I am wrong.

Regards
Srinath

|0| = -0 = 0. So, what I've written is correct.
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Intern
Joined: 05 Feb 2017
Posts: 3

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25 Nov 2017, 02:36
I think this is a high-quality question and I agree with explanation. Brilliant
Intern
Joined: 11 Aug 2017
Posts: 5
WE: Account Management (Energy and Utilities)

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06 Dec 2017, 22:02
I think i am missing something.

Can you explain why "A" can be eliminated? Isn't -0.5 less than than 1?

A. x>1. Not necessarily true since x could be -0.5;
Math Expert
Joined: 02 Sep 2009
Posts: 50623

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06 Dec 2017, 22:14
DouglassJensen wrote:
I think i am missing something.

Can you explain why "A" can be eliminated? Isn't -0.5 less than than 1?

A. x>1. Not necessarily true since x could be -0.5;

We know that −1 < x < 0 or x > 1. The question asks to determine which of the options MUST be true.

A says: x > 1. This options is NOT always true because x could be from any number from −1 < x < 0, and if it is, then x > 1 won't be true. Please re-read the whole discussion again and follow the links provided there.

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_________________
Intern
Joined: 09 Apr 2018
Posts: 12

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05 Jul 2018, 01:46
But B would fail for x = 1.
As it is a must be true case it will fail for x = 1 (where 1 > -1).
So B can not be the answer.
Math Expert
Joined: 02 Sep 2009
Posts: 50623

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21 Jul 2018, 11:19
dpkgirdhar wrote:
I think this is a poor-quality question and I don't agree with the explanation. YOUR ANSWER IS INCORRECT. CHECK IT WHEN X=1

You did not understand the question and the solution. Also, it seems that you did not read the discussion. Please read the whole discussion before posting a question.

To understand the underline concept better practice other Trickiest Inequality Questions Type: Confusing Ranges.

P.S. ALL questions in the tests are correct.
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Intern
Joined: 27 Jun 2018
Posts: 2

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09 Nov 2018, 22:32
I think this is a high-quality question and I don't agree with the explanation. What if you take X=0.5?
LHS becomes 0.5/0.5=1, RHS becomes 0.5
According to equation: LHS<RHS i.e 1<0.5 but that's not true. Hence according to me option B is not right
Math Expert
Joined: 02 Sep 2009
Posts: 50623

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10 Nov 2018, 05:47
ayushrazdan wrote:
I think this is a high-quality question and I don't agree with the explanation. What if you take X=0.5?
LHS becomes 0.5/0.5=1, RHS becomes 0.5
According to equation: LHS<RHS i.e 1<0.5 but that's not true. Hence according to me option B is not right

Unfortunately you did not understand the question and the solution. Also, it seems that you did not read the discussion. Please read the whole discussion before posting a question.

To understand the underline concept better practice other Trickiest Inequality Questions Type: Confusing Ranges.
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Manager
Joined: 18 Aug 2017
Posts: 215
Concentration: Healthcare, Marketing

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10 Nov 2018, 07:57
If x≠0x≠0 and x|x|<xx|x|<x, which of the following must be true?

A. x>1x>1
B. x>−1x>−1
C. |x|<1|x|<1
D. |x|&gt;1
E. −1<x<0

From given stem, we need to plug in values in relation to given set of options, for which only option B is valid
Re: M09-22 &nbs [#permalink] 10 Nov 2018, 07:57

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# M09-22

Moderators: chetan2u, Bunuel

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