Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
16 Sep 2014, 00:45
Kudos
Bookmarks
If \(x\), \(y\), and \(z\) are positive integers, is \(x\%\) of \(y\) greater than \(y\%\) of \(z\)?
(1) \(x = z\)
(2) \(z - y = y - x\)
(1) \(x = z\)
(2) \(z - y = y - x\)
16 Sep 2014, 00:45
Kudos
Bookmarks
Official Solution:
If \(x\), \(y\), and \(z\) are positive integers, is \(x\%\) of \(y\) greater than \(y\%\) of \(z\)?
The question essentially asks: is \(\frac{x}{100} * y > \frac{y}{100} * z\)? Given that \(y\) is a positive integer, we can safely divide both sides by \(\frac{y}{100}\). Thus, the question simplifies to: is \(x > z\)? It's important to note that the answer does not depend on the value of \(y\).
(1) \(x=z\).
The answer to the question is NO. This is sufficient.
(2) \(z-y=y-x\).
If we rearrange, we get \(x+z=2y\). This doesn't provide enough information to determine whether \(x > z\). Thus, it's insufficient.
Answer: A
If \(x\), \(y\), and \(z\) are positive integers, is \(x\%\) of \(y\) greater than \(y\%\) of \(z\)?
The question essentially asks: is \(\frac{x}{100} * y > \frac{y}{100} * z\)? Given that \(y\) is a positive integer, we can safely divide both sides by \(\frac{y}{100}\). Thus, the question simplifies to: is \(x > z\)? It's important to note that the answer does not depend on the value of \(y\).
(1) \(x=z\).
The answer to the question is NO. This is sufficient.
(2) \(z-y=y-x\).
If we rearrange, we get \(x+z=2y\). This doesn't provide enough information to determine whether \(x > z\). Thus, it's insufficient.
Answer: A
General Discussion
19 Aug 2015, 04:30
Kudos
Bookmarks
For this question best is to use some smart numbers i think
for statement 1
let x= 5 y = 100
z= x = 5 --> since given
so lets check : is 5% of 100 > 100% of 5 - - no they are equal. - this will hold true for any positive number for x and y and z
so sufficient
Statement 2:
first simplify - the given z-x=y-x becomes x+z =2y
Again smart numbers - choose numbers that satisfy the above condition
Let y =5. -- so x and z should be 2 numbers that add up to 2y here it is 10
so for example x can be 7 and z can be 3
lets check. is 7% of 5 > 5% of 3? --> yes.. greater percent of a bigger number > smaller percent of a smaller number
So lets see if we can get an opposite ans
what if x = 3 and z = 7 ( they still add up to 10 which is 2y)
now is 3%of 5 > 5% of 7? ---No it is not...
So this statement is not suff
So
for statement 1
let x= 5 y = 100
z= x = 5 --> since given
so lets check : is 5% of 100 > 100% of 5 - - no they are equal. - this will hold true for any positive number for x and y and z
so sufficient
Statement 2:
first simplify - the given z-x=y-x becomes x+z =2y
Again smart numbers - choose numbers that satisfy the above condition
Let y =5. -- so x and z should be 2 numbers that add up to 2y here it is 10
so for example x can be 7 and z can be 3
lets check. is 7% of 5 > 5% of 3? --> yes.. greater percent of a bigger number > smaller percent of a smaller number
So lets see if we can get an opposite ans
what if x = 3 and z = 7 ( they still add up to 10 which is 2y)
now is 3%of 5 > 5% of 7? ---No it is not...
So this statement is not suff
So
