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M11-36

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M11-36  [#permalink]

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New post 16 Sep 2014, 00:45
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A
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E

Difficulty:

  35% (medium)

Question Stats:

64% (01:15) correct 36% (01:27) wrong based on 92 sessions

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Because of weight limits, a lorry can carry a maximum of 20 crates of apples. The weight of a crate of oranges is \(\frac{3}{4}\) the weight of a crate of apples. If 10 crates of apples were loaded into the lorry, what is the maximum number of crates of oranges that the lorry can still accommodate?

A. 8
B. 9
C. 12
D. 13
E. 14

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Re M11-36  [#permalink]

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New post 16 Sep 2014, 00:45
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Official Solution:

Because of weight limits, a lorry can carry a maximum of 20 crates of apples. The weight of a crate of oranges is \(\frac{3}{4}\) the weight of a crate of apples. If 10 crates of apples were loaded into the lorry, what is the maximum number of crates of oranges that the lorry can still accommodate?

A. 8
B. 9
C. 12
D. 13
E. 14

There's still room for 10 crates of apples. The weight of 10 crates of apples is the same as the weight of \(10*(\frac{4}{3}) = 13\frac{1}{3}\) crates of oranges. Because the number of crates has to be an integer, the lorry can accommodate a maximum of 13 crates of oranges.

Answer: D
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Re: M11-36  [#permalink]

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New post 05 Sep 2015, 10:14
Bunuel wrote:
Because of weight limits, a lorry can carry a maximum of 20 crates of apples. The weight of a crate of oranges is \(\frac{3}{4}\) the weight of a crate of apples. If 10 crates of apples were loaded into the lorry, what is the maximum number of crates of oranges that the lorry can still accommodate?

A. 8
B. 9
C. 12
D. 13
E. 14



VeritasPrepKarishma,

This question can be easily done via basic math as described above.

However, i was wondering is it possible to apply the weighted average method to solve this question?

\((c1w1 + c2w2)/(w1+w2)\) = \(Cavg\)
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Re: M11-36  [#permalink]

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New post 28 Jul 2017, 21:31
Hi Bunnel,

If the question is what is the number of crates of oranges that the lorry can still accommodate ? or How many crates of oranges that the lorry can still accommodate despite the fact that lorry can accommodate a maximum of 20 crates of apples ?

Then in that case i believe answer is 14 (E).

Thanks
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Re: M11-36  [#permalink]

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New post 28 Jul 2017, 22:30
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Let's say, the weight of one crate of apples is 4 kg

So, the wt of one crate of oranges becomes 3/4(4) = 3 kg

Capacity of truck is 4kg * 20 crates =80 kg

10 crates of apples is already loaded i.e 40 kg and the balance capacity is 80-40=40 kg

No of crates of orages, the truck can accomodate is 40/3 = 13.33 = 13 crates
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Re: M11-36  [#permalink]

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New post 29 Jul 2017, 23:26
Thanks srikanth, i got your point. I was thinking something else so got lost. I was thinking about quantities placed on crates.
13 1/3 is about crates.

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Re: M11-36   [#permalink] 29 Jul 2017, 23:26
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