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M12-03

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M12-03  [#permalink]

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New post 16 Sep 2014, 00:46
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A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

84% (02:06) correct 16% (02:07) wrong based on 50 sessions

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Re M12-03  [#permalink]

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New post 16 Sep 2014, 00:46
Official Solution:

In a bunch of letters, 60 were found to be anonymous and typewritten. If 15 percent of the typewritten letters were anonymous, how many letters that were not anonymous were typewritten?

A. 120
B. 180
C. 340
D. 360
E. 400

15 percent of typewritten letters = 60. Hence, there are in all \(\frac{60}{15}*100 = 400\) typewritten letters. Of these 400 letters, 60 are anonymous. Therefore, \(400 - 60 = 340\) letters are typewritten and not anonymous.

Answer: C
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M12-03  [#permalink]

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New post 02 Aug 2016, 06:10
Bunuel

How come 15% of typewritten letters are equal to 60 when the # of typewritten and anonymous letter are 60? We have to equate it only to the anonymous one? What am I missing here? :roll:
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Re: M12-03  [#permalink]

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New post 02 Aug 2016, 07:09
1
Given 1: 60 were both anonymous and typewritten
Given 2: 15%(Typewritten) were Anonymous

How many typewritten letters are anonymous = 60 (its just rephrase of above Given 1 statement in question)
0.15(t) = 60 (from Given statement 2)
t = 400
Only Anonymous letters = Total Typewritten - Both Typewritten AND Anonymous
= 400 - 60
= 340
Answer: C
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Re: M12-03  [#permalink]

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New post 02 Aug 2016, 08:14
Thanks pluto82 This helps.
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Re: M12-03  [#permalink]

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New post 03 Aug 2016, 23:31
Bunuel wrote:
In a bunch of letters, 60 were found to be anonymous and typewritten. If 15 percent of the typewritten letters were anonymous, how many letters that were not anonymous were typewritten?

A. 120
B. 180
C. 340
D. 360
E. 400



15 % -> 60 letters
100 % -> 60/15 x 100 = 400
Anonymous + Not Anonymous letters =400
=> Not Anonymous =400 -60 =340
Option C
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Re M12-03  [#permalink]

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New post 10 Apr 2019, 07:05
I think this is a poor-quality question and the explanation isn't clear enough, please elaborate. There seems to be some issue with the explanation,

According to the question,
60 = anonymous + typewritten

and 15 % typewritten letters(anonymous and typewritten both + typewritten only) = anonymous only + anonymous and typewritten both
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Re: M12-03  [#permalink]

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New post 10 Apr 2019, 17:58
Bunuel wrote:
In a bunch of letters, 60 were found to be anonymous and typewritten. If 15 percent of the typewritten letters were anonymous, how many letters that were not anonymous were typewritten?

A. 120
B. 180
C. 340
D. 360
E. 400


Using sets,
No of typewritten letters=\(\frac{60}{15}*100=400\).
No of letters that were not anonymous but typewritten=\(400-60=340.\)

IMO, Option C.
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Re: M12-03   [#permalink] 10 Apr 2019, 17:58
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