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M12-33

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M12-33  [#permalink]

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New post 16 Sep 2014, 00:48
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

80% (01:39) correct 20% (01:51) wrong based on 79 sessions

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Math Expert
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Re M12-33  [#permalink]

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New post 16 Sep 2014, 00:48
Official Solution:

Two books together cost $1.35. If \(\frac{35}{100}\) of the price of the cheaper book equals \(\frac{28}{100}\) of the price of the more expensive book, what is the price of the cheaper book?

A. $0.35
B. $0.40
C. $0.55
D. $0.60
E. $0.65


\(C\) represents the price of the cheaper book, \(E\) represents the price of the more expensive book. Build a system of equations:
\(0.35C = 0.28E\)
\(C + E = 1.35\)

From this equation, \(C = 0.60\).


Answer: D
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Re: M12-33  [#permalink]

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New post 24 Jun 2016, 16:49
I know it's pretty straight forward,
but could someone expand on how to quickly solve this equation? in 2 minutes It tangled up on me,
thank you
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Re: M12-33  [#permalink]

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New post 17 Aug 2016, 07:36
1
divide 0,35/0,28 and you will have 5/4. easier!
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Re: M12-33  [#permalink]

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New post 21 Oct 2018, 03:11
...
C+E=1.35
5C=4E

Therefore,
C=1.35 - E
5(1.35 - E) = 4E
6.75-5E=4E
6.75=9E

E= 6.75 / 9 = 0.75

Hence C is 1.35 - 0.75 = 0.60
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Re: M12-33   [#permalink] 21 Oct 2018, 03:11
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