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Math Expert V
Joined: 02 Sep 2009
Posts: 58453

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Difficulty:   15% (low)

Question Stats: 80% (01:39) correct 20% (01:51) wrong based on 79 sessions

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Two books together cost $1.35. If $$\frac{35}{100}$$ of the price of the cheaper book equals $$\frac{28}{100}$$ of the price of the more expensive book, what is the price of the cheaper book? A.$0.35
B. $0.40 C.$0.55
D. $0.60 E.$0.65

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Math Expert V
Joined: 02 Sep 2009
Posts: 58453

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Official Solution:

Two books together cost $1.35. If $$\frac{35}{100}$$ of the price of the cheaper book equals $$\frac{28}{100}$$ of the price of the more expensive book, what is the price of the cheaper book? A.$0.35
B. $0.40 C.$0.55
D. $0.60 E.$0.65

$$C$$ represents the price of the cheaper book, $$E$$ represents the price of the more expensive book. Build a system of equations:
$$0.35C = 0.28E$$
$$C + E = 1.35$$

From this equation, $$C = 0.60$$.

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I know it's pretty straight forward,
but could someone expand on how to quickly solve this equation? in 2 minutes It tangled up on me,
thank you
Intern  B
Joined: 04 Jan 2016
Posts: 6

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1
divide 0,35/0,28 and you will have 5/4. easier!
Intern  Joined: 30 Jul 2017
Posts: 1

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...
C+E=1.35
5C=4E

Therefore,
C=1.35 - E
5(1.35 - E) = 4E
6.75-5E=4E
6.75=9E

E= 6.75 / 9 = 0.75

Hence C is 1.35 - 0.75 = 0.60 Re: M12-33   [#permalink] 21 Oct 2018, 03:11
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