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# M13 Q10

Author Message
Manager
Joined: 12 Dec 2009
Posts: 117

Kudos [?]: 119 [0], given: 6

Location: United States (AL)
Concentration: Finance
Schools: Harvard Business School (HBS) - Class of 2014
GMAT 1: 770 Q50 V46
GPA: 3.91
WE: Corporate Finance (Venture Capital)

### Show Tags

05 May 2010, 07:26
Sorry if this has been asked before. Can't seem to do a search on "m13".

During the break of a football match, the coach will make 3 substitutions. If the team consists of 11 players among which there are 2 forwards, what is the probability that none of the forwards will be substituted?

The answer is 28/55 and I didn't quite comprehend the solution.

I approached it as: first substitution - 9/11 chance forward won't be replaced. Second sub: 8/10 (minus the already replaced one). Third: 7/9. So prob that the 2 forwards won't be replaced the whole time is (9/11)(8/10)(7/9).

If anyone can provide insight it'd be greatly appreciated! Thanks!

Kudos [?]: 119 [0], given: 6

Manager
Joined: 08 May 2010
Posts: 141

Kudos [?]: 67 [0], given: 39

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12 May 2010, 00:13
It looks to me like you did it right. What is your specific question?

Kudos [?]: 67 [0], given: 39

Intern
Joined: 20 Apr 2010
Posts: 17

Kudos [?]: 6 [0], given: 3

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15 May 2010, 10:07
You are right my friend 9/11*8/10*7/9 = 56/110 = 28/55

Kudos [?]: 6 [0], given: 3

Re: M13 Q10   [#permalink] 15 May 2010, 10:07
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# M13 Q10

Moderator: Bunuel

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