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24 Dec 2011, 03:51
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B
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73% (00:54) correct
27%
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How many three-digit integers exist such that all their digits are even?
A. 80
B. 100
C. 120
D. 125
E. 135
A. 80
B. 100
C. 120
D. 125
E. 135
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24 Dec 2011, 04:49
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The hundreds digit can be filled in 4 ways (2,4,6,8 but not 0 as in that case the number will become two digit instead of three digit) and the next two can be filled in 5 ways each. Therefore total such numbers = 4 x 5 x 5 = 100
19 Jun 2014, 02:46
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Bunuel,
This is Quantitative :: Problem solving :: Probability & Combinations :: M13-14
0 is also an even integer
so last digit can be filled in 5 ways- 0,2,4,6,8
for both second and third digit there are 5 possibilities-
5 X 5 X 5 = 125
_______________
This is the solution given at Gmatclubtest
The first digit can be any of the four: 2, 4, 6, or 8. For both second and third digits, there are 5 possibilities. The answer is 4∗5∗5=100.
The correct answer is B
This is Quantitative :: Problem solving :: Probability & Combinations :: M13-14
0 is also an even integer
so last digit can be filled in 5 ways- 0,2,4,6,8
for both second and third digit there are 5 possibilities-
5 X 5 X 5 = 125
_______________
This is the solution given at Gmatclubtest
The first digit can be any of the four: 2, 4, 6, or 8. For both second and third digits, there are 5 possibilities. The answer is 4∗5∗5=100.
The correct answer is B
