Official Solution:If set \(S\) consists of even number of integers, is the median of set \(S\) negative? First, note that since the set contains an even number of integers, the median will be the average of the two middle elements.
(1) Exactly half of all elements of set \(S\) are positive.
The above implies that the remaining half of the elements in the set are composed of either negative elements only, or negative elements and 0. In the first scenario, the median would be \(\frac{negative + positive}{2}\), which could be positive, negative or zero depending on the specific values of these two middle elements. However, in the second scenario, the median would be \(\frac{0 + positive}{2}=positive\). This statement alone is not sufficient.
(2) The largest negative element of set \(S\) is -1. This statement alone is not sufficient.
(1)+(2) From the above, we know that exactly half of the elements in \(S\) are positive, and the largest negative element is -1. There are two possible scenarios for the median value of \(S\):
If \(S\) contains 0, then the median value would be \(\frac{0 + positive}{2}=positive\).
If \(S\) does not contain 0, then the median value would be \(\frac{-1+\text{positive integer}}{2}=\text{0 or positive}\).
Therefore, in either case, the answer to the question of whether the median of \(S\) is negative is NO, making the statements together sufficient.
Answer: C