Official Solution:If \(x\) is a prime number, how many distinct positive factors does \(x^3\) have?A. 2
B. 3
C. 4
D. 5
E. 6
Since \(x\) is a prime number, \(x^3\) will have 4 distinct positive divisors: 1, \(x\), \(x^2\), and \(x^3\). For example, \(2^3\) has the factors 1, 2, 4, and 8; similarly, \(3^3\) has the factors 1, 3, 9, and 27.
Finding the Number of Factors of an Integer First, make the prime factorization of an integer \(n = a^p * b^q * c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\), and \(p\), \(q\), and \(r\) are their respective powers.
The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\).
NOTE: this will include 1 and \(n\) itself.
Example: Finding the number of all factors of 450: \(450 = 2^1 * 3^2 * 5^2\)
The total number of factors of 450, including 1 and 450 itself, is \((1+1)(2+1)(2+1) = 2*3*3 = 18\) factors.
Answer: C