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M15-33

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M15-33  [#permalink]

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New post 16 Sep 2014, 00:57
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60% (00:53) correct 40% (00:51) wrong based on 121 sessions

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If 4 small boxes and 5 big boxes weigh the same as 11 small boxes and 2 big boxes, how much does one small box weigh?


(1) One big box weighs 1 kg more than one small box.

(2) The ratio of the weight of one small box to the weight of one big box is \(\frac{3}{7}\).

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M15-33  [#permalink]

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New post 16 Sep 2014, 00:57
1
Official Solution:

If 4 small boxes and 5 big boxes weigh the same as 11 small boxes and 2 big boxes, how much does one small box weigh?

Given: \(4s+5b=11s+2b\), so \(3b=7s\). Question: \(s=?\)

(1) One big box weighs 1 kg more than one small box. Given: \(b=s+1\). Substitute \(b\): \(3(s+1)=7s\), which gives \(s=\frac{3}{4}\). Sufficient.

(2) The ratio of the weight of one small box to the weight of one big box is \(\frac{3}{7}\). Given: \(\frac{s}{b}=\frac{3}{7}\), or \(3b=7s\), the same info as in the stem. Not sufficient.


Answer: A
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Re: M15-33  [#permalink]

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New post 02 Dec 2014, 12:37
Bunuel wrote:
Official Solution:


Given: \(4s+5b=11s+2b\), so \(3b=7s\). Question: \(s=?\)

(1) One big box weighs 1 kg more than one small box. Given: \(b=s+1\). Substitute \(b\): \(3(s+1)=7s\), which gives \(s=\frac{3}{4}\). Sufficient.

(2) The ratio of the weight of one small box to the weight of one big box is \(\frac{3}{7}\). Given: \(\frac{s}{b}=\frac{3}{7}\), or \(3b=7s\), the same info as in the stem. Not sufficient.


Answer: A



with s=3/4, is that telling us that the small box weighs 3/4 kg of that it is 3/4 the weight of the larger box?
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Re: M15-33  [#permalink]

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New post 03 Dec 2014, 04:12
bsmith37 wrote:
Bunuel wrote:
Official Solution:


Given: \(4s+5b=11s+2b\), so \(3b=7s\). Question: \(s=?\)

(1) One big box weighs 1 kg more than one small box. Given: \(b=s+1\). Substitute \(b\): \(3(s+1)=7s\), which gives \(s=\frac{3}{4}\). Sufficient.

(2) The ratio of the weight of one small box to the weight of one big box is \(\frac{3}{7}\). Given: \(\frac{s}{b}=\frac{3}{7}\), or \(3b=7s\), the same info as in the stem. Not sufficient.


Answer: A



with s=3/4, is that telling us that the small box weighs 3/4 kg of that it is 3/4 the weight of the larger box?


\(s=\frac{3}{4}\) means that the small box weighs 3/4 kg and the big box weighs \(3b=7*\frac{3}{4}\) --> \(b = \frac{7}{4}\) kg.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: M15-33  [#permalink]

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New post 10 Feb 2017, 07:45
Option A it is. As per the question, 4S+5B=11S+2B. From this , S/B=3/7. We need to find S.

Statement 1 : b=s+1. This is sufficient.
Statement 2 : S/B=3/7. No new info. Hence in-sufficient.

The answer must be option A.
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Re: M15-33 &nbs [#permalink] 10 Feb 2017, 07:45
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