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06 Oct 2009, 13:53
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If in a six-digit integer \(N\), \(F(k)\) is the value of the \(k-th\) digit, is \(N\) divisible by 7 (For example, \(F(4)\) is the value of the hundreds digit of \(N\) )?
(1) \(F(1) = F(4), F(2) = F(5), F(3) = F(6)\)
(2) \(F(1) = F(2) = ... = F(6)\)
(C) 2008 GMAT Club - m15#29
SOLUTION:
(1) \(F(1) = F(4), F(2) = F(5), F(3) = F(6)\)
(2) \(F(1) = F(2) = ... = F(6)\)
(C) 2008 GMAT Club - m15#29
SOLUTION:
Statements (1) and (2) by themselves are sufficient. S1 tells us that the last three digits of \(N\) are the same as the first three digits: \(N = abcabc\) . Note that \(N = abc*1000 + abc = abc*1001\) . As 1001 is divisible by 7, \(N\) is also divisible by 7.
The correct answer is D.
The correct answer is D.
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06 Oct 2009, 13:59
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I believe there is an error in this question.
If, as it says, F(4) is the value of the hundreds digit, then F(1) is the value of the decimal digit of N.
Given that N is an integer, then F(1)=0.
F(1)=F(2)=F(3)=F(4)=F(5)=F(6)=0 --> N=0 and it is not a 6 digit integer. This contradicts the question stem.
Or am I missing something?
If, as it says, F(4) is the value of the hundreds digit, then F(1) is the value of the decimal digit of N.
Given that N is an integer, then F(1)=0.
F(1)=F(2)=F(3)=F(4)=F(5)=F(6)=0 --> N=0 and it is not a 6 digit integer. This contradicts the question stem.
Or am I missing something?
