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Intern
Joined: 06 Apr 2016
Posts: 22
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Hello Bunuel,
What if : set S = {1,2,3,4} ; Mean=2.5
subset of S ={1,2} ; Mean =1.5
Then option 2 " All elements in set S are equal" does not fit in.
Please let me where am i going wrong.
Thanks,
Saba
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Math Expert
Joined: 02 Sep 2009
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Re: M16-23
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 24 Aug 2017, 12:25
saba@4010 wrote: Hello Bunuel,
What if : set S = {1,2,3,4} ; Mean=2.5
subset of S ={1,2} ; Mean =1.5
Then option 2 " All elements in set S are equal" does not fit in.
Please let me where am i going wrong.
Thanks,
Saba "The mean of set \(S\) does not exceed mean of ANY subset of set \(S\)". Your example does not work.
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Bunuel wrote: saba@4010 wrote: Hello Bunuel,
What if : set S = {1,2,3,4} ; Mean=2.5
subset of S ={1,2} ; Mean =1.5
Then option 2 " All elements in set S are equal" does not fit in.
Please let me where am i going wrong.
Thanks,
Saba "The mean of set \(S\) does not exceed mean of ANY subset of set \(S\)". Your example does not work. Thanks Bunuel ,understood ! Posted from my mobile device
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Current Student
Joined: 12 Feb 2015
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Location: India
GPA: 3.84
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Re: M16-23
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25 Aug 2017, 02:47
Just need to confirm one thing.S={1,2,3} then can the subset be like A={1,1,}
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Joined: 02 Sep 2009
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Re: M16-23
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25 Aug 2017, 05:50
himanshukamra2711 wrote: Just need to confirm one thing.S={1,2,3} then can the subset be like A={1,1,} No, you don't have three 1's in S. Subsets of {1, 2, 3} are: {1, 2, 3} {1, 2} {1, 3} {2, 3} {1} {2} {3} {} - an empty set.
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Joined: 14 May 2017
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Re: M16-23
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29 Aug 2017, 06:04
Bunuel wrote: ManSab wrote: 1. Set S contains only one element.
Does it mean count of element or value of element?
My understanding is that set S has only one element by count not by value... therefore {X,X...} is not possible. Please help understand. Option 1, Set S contains only one element means that there is only one elements in S: {X}. This option is not necessarily true. Please re-read the solution. Hi, I am confused with second option. If i didn't misunderstood the question, it state that mean of Set S should be less than mean of its subset. Lets Consider: S =(2,4,6) - mean =4 S'= (4,6) - mean = 5 Here Set S has different values. Please advise. Thanks, Arpit
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Re: M16-23
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29 Aug 2017, 06:07
NeverGiveUp- Arpit wrote: Bunuel wrote: ManSab wrote: 1. Set S contains only one element.
Does it mean count of element or value of element?
My understanding is that set S has only one element by count not by value... therefore {X,X...} is not possible. Please help understand. Option 1, Set S contains only one element means that there is only one elements in S: {X}. This option is not necessarily true. Please re-read the solution. Hi, I am confused with second option. If i didn't misunderstood the question, it state that mean of Set S should be less than mean of its subset. Lets Consider: S =(2,4,6) - mean =4 S'= (4,6) - mean = 5 Here Set S has different values. Please advise. Thanks, Arpit I'd advice to re-read the stem and the solution carefully and go through the discussion once more.
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Re: M16-23
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29 Aug 2017, 06:56
[quote="Bunuel"
I'd advice to re-read the stem and the solution carefully and go through the discussion once more.[/quote]
Got it. Thanks mate.
I overlooked the word 'Any '.
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Joined: 07 Oct 2015
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Re: M16-23
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19 Sep 2017, 00:48
What is S= 1,2,3,4,5
Mean=3
Median=3
Subset(4,5); Mean =4.5>3
So, Statment 3: False
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Re: M16-23
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19 Sep 2017, 00:50
3ksnikhil wrote: What is S= 1,2,3,4,5
Mean=3
Median=3
Subset(4,5); Mean =4.5>3
So, Statment 3: False "The mean of set \(S\) does not exceed mean of ANY subset of set \(S\)". Your example does not work.
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Re: M16-23
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22 Dec 2017, 15:18
Hello !
For case III, let's take an example where the median of set S equals the mean of set S : set S = {1,2,3}, mean=median=2. In that case, {1} is a subset of set S and 2>1. Conclusion: the mean of set S DOES exceed mean of a subset of set S
How is III still correct ?
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Re: M16-23
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23 Dec 2017, 01:14
mahagmat wrote: Hello !
For case III, let's take an example where the median of set S equals the mean of set S : set S = {1,2,3}, mean=median=2. In that case, {1} is a subset of set S and 2>1. Conclusion: the mean of set S DOES exceed mean of a subset of set S
How is III still correct ? This is explained many times. Please read the whole thread.
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Re: M16-23
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21 Jun 2018, 00:03
Hi Bunuel,
"If the mean of set S does not exceed mean of any subset of set S''
Does it have to be true that Mean of S and Mean of any subset of S is equal? What if set S has negative numbers?
For Ex:- S= {3,4,5,6,-7} and subset of S is {3,4,5,6}. Here mean does not exceed but is lower that its subset.
In above example none of the three statement holds true? Could you please advise.
Thank you.
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Re: M16-23
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21 Jun 2018, 00:16
hrishipatil72 wrote: Hi Bunuel,
"If the mean of set S does not exceed mean of any subset of set S''
Does it have to be true that Mean of S and Mean of any subset of S is equal? What if set S has negative numbers?
For Ex:- S= {3,4,5,6,-7} and subset of S is {3,4,5,6}. Here mean does not exceed but is lower that its subset.
In above example none of the three statement holds true? Could you please advise.
Thank you. The mean of {3, 4, 5, 6, -7} is 2.2. The mean of one of the subset of the above set, {3, -7}, is 2. So, your example is not valid. The stem says: "The mean of set \(S\) does not exceed mean of ANY subset of set \(S\)".
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Re M16-23
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10 Aug 2018, 03:47
I don't agree with the explanation. Statement III.
If median of set = mean of set
eg. mean {0,1,2} = median {0,1,2} = 1
here, mean exceeds the subset of set which is {2}.
Only II should be the corret answer?
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Re: M16-23
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10 Aug 2018, 03:59
MittalMewada wrote: I don't agree with the explanation. Statement III.
If median of set = mean of set
eg. mean {0,1,2} = median {0,1,2} = 1
here, mean exceeds the subset of set which is {2}.
Only II should be the corret answer? I would not address your doubt. Instead I'd advice to read the whole thread. Your question is answered there many times.
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Re M16-23
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16 Aug 2019, 07:42
I think this is a high-quality question and I don't agree with the explanation.
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Re: M16-23
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16 Aug 2019, 07:46
Koushini wrote: I think this is a high-quality question and I don't agree with the explanation.
Posted from my mobile device The solution is 100% correct. Please read the whole discussion. Hope it helps.
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