Oct 22 08:00 AM PDT  09:00 AM PDT Join to learn strategies for tackling the longest, wordiest examples of Counting, Sets, & Series GMAT questions Oct 22 09:00 AM PDT  10:00 AM PDT Watch & learn the Do's and Don’ts for your upcoming interview Oct 22 08:00 PM PDT  09:00 PM PDT On Demand for $79. For a score of 4951 (from current actual score of 40+) AllInOne Standard & 700+ Level Questions (150 questions) Oct 23 08:00 AM PDT  09:00 AM PDT Join an exclusive interview with the people behind the test. If you're taking the GMAT, this is a webinar you cannot afford to miss! Oct 26 07:00 AM PDT  09:00 AM PDT Want to score 90 percentile or higher on GMAT CR? Attend this free webinar to learn how to prethink assumptions and solve the most challenging questions in less than 2 minutes. Oct 27 07:00 AM EDT  09:00 AM PDT Exclusive offer! Get 400+ Practice Questions, 25 Video lessons and 6+ Webinars for FREE.
Author 
Message 
TAGS:

Hide Tags

Intern
Joined: 06 Apr 2016
Posts: 22

Hello Bunuel,
What if : set S = {1,2,3,4} ; Mean=2.5 subset of S ={1,2} ; Mean =1.5
Then option 2 " All elements in set S are equal" does not fit in. Please let me where am i going wrong.
Thanks, Saba



Math Expert
Joined: 02 Sep 2009
Posts: 58396

Re: M1623
[#permalink]
Show Tags
24 Aug 2017, 12:25
saba@4010 wrote: Hello Bunuel,
What if : set S = {1,2,3,4} ; Mean=2.5 subset of S ={1,2} ; Mean =1.5
Then option 2 " All elements in set S are equal" does not fit in. Please let me where am i going wrong.
Thanks, Saba "The mean of set \(S\) does not exceed mean of ANY subset of set \(S\)". Your example does not work.
_________________



Intern
Joined: 06 Apr 2016
Posts: 22

Bunuel wrote: saba@4010 wrote: Hello Bunuel,
What if : set S = {1,2,3,4} ; Mean=2.5 subset of S ={1,2} ; Mean =1.5
Then option 2 " All elements in set S are equal" does not fit in. Please let me where am i going wrong.
Thanks, Saba "The mean of set \(S\) does not exceed mean of ANY subset of set \(S\)". Your example does not work. Thanks Bunuel ,understood ! Posted from my mobile device



Current Student
Joined: 12 Feb 2015
Posts: 54
Location: India
GPA: 3.84

Re: M1623
[#permalink]
Show Tags
25 Aug 2017, 02:47
Just need to confirm one thing.S={1,2,3} then can the subset be like A={1,1,}



Math Expert
Joined: 02 Sep 2009
Posts: 58396

Re: M1623
[#permalink]
Show Tags
25 Aug 2017, 05:50
himanshukamra2711 wrote: Just need to confirm one thing.S={1,2,3} then can the subset be like A={1,1,} No, you don't have three 1's in S. Subsets of {1, 2, 3} are: {1, 2, 3} {1, 2} {1, 3} {2, 3} {1} {2} {3} {}  an empty set.
_________________



Intern
Joined: 14 May 2017
Posts: 44

Re: M1623
[#permalink]
Show Tags
29 Aug 2017, 06:04
Bunuel wrote: ManSab wrote: 1. Set S contains only one element. Does it mean count of element or value of element? My understanding is that set S has only one element by count not by value... therefore {X,X...} is not possible. Please help understand. Option 1, Set S contains only one element means that there is only one elements in S: {X}. This option is not necessarily true. Please reread the solution. Hi, I am confused with second option. If i didn't misunderstood the question, it state that mean of Set S should be less than mean of its subset. Lets Consider: S =(2,4,6)  mean =4 S'= (4,6)  mean = 5 Here Set S has different values. Please advise. Thanks, Arpit



Math Expert
Joined: 02 Sep 2009
Posts: 58396

Re: M1623
[#permalink]
Show Tags
29 Aug 2017, 06:07
NeverGiveUp Arpit wrote: Bunuel wrote: ManSab wrote: 1. Set S contains only one element. Does it mean count of element or value of element? My understanding is that set S has only one element by count not by value... therefore {X,X...} is not possible. Please help understand. Option 1, Set S contains only one element means that there is only one elements in S: {X}. This option is not necessarily true. Please reread the solution. Hi, I am confused with second option. If i didn't misunderstood the question, it state that mean of Set S should be less than mean of its subset. Lets Consider: S =(2,4,6)  mean =4 S'= (4,6)  mean = 5 Here Set S has different values. Please advise. Thanks, Arpit I'd advice to reread the stem and the solution carefully and go through the discussion once more.
_________________



Intern
Joined: 14 May 2017
Posts: 44

Re: M1623
[#permalink]
Show Tags
29 Aug 2017, 06:56
[quote="Bunuel"
I'd advice to reread the stem and the solution carefully and go through the discussion once more.[/quote]
Got it. Thanks mate.
I overlooked the word 'Any '.
Posted from my mobile device
Posted from my mobile device



Intern
Joined: 07 Oct 2015
Posts: 7

Re: M1623
[#permalink]
Show Tags
19 Sep 2017, 00:48
What is S= 1,2,3,4,5 Mean=3 Median=3 Subset(4,5); Mean =4.5>3 So, Statment 3: False



Math Expert
Joined: 02 Sep 2009
Posts: 58396

Re: M1623
[#permalink]
Show Tags
19 Sep 2017, 00:50
3ksnikhil wrote: What is S= 1,2,3,4,5 Mean=3 Median=3 Subset(4,5); Mean =4.5>3 So, Statment 3: False "The mean of set \(S\) does not exceed mean of ANY subset of set \(S\)". Your example does not work.
_________________



Intern
Joined: 19 Jun 2017
Posts: 2

Re: M1623
[#permalink]
Show Tags
22 Dec 2017, 15:18
Hello ! For case III, let's take an example where the median of set S equals the mean of set S : set S = {1,2,3}, mean=median=2. In that case, {1} is a subset of set S and 2>1. Conclusion: the mean of set S DOES exceed mean of a subset of set S How is III still correct ?



Math Expert
Joined: 02 Sep 2009
Posts: 58396

Re: M1623
[#permalink]
Show Tags
23 Dec 2017, 01:14
mahagmat wrote: Hello ! For case III, let's take an example where the median of set S equals the mean of set S : set S = {1,2,3}, mean=median=2. In that case, {1} is a subset of set S and 2>1. Conclusion: the mean of set S DOES exceed mean of a subset of set S How is III still correct ? This is explained many times. Please read the whole thread.
_________________



Intern
Joined: 23 Aug 2016
Posts: 10

Re: M1623
[#permalink]
Show Tags
21 Jun 2018, 00:03
Hi Bunuel,
"If the mean of set S does not exceed mean of any subset of set S''
Does it have to be true that Mean of S and Mean of any subset of S is equal? What if set S has negative numbers?
For Ex: S= {3,4,5,6,7} and subset of S is {3,4,5,6}. Here mean does not exceed but is lower that its subset.
In above example none of the three statement holds true? Could you please advise.
Thank you.



Math Expert
Joined: 02 Sep 2009
Posts: 58396

Re: M1623
[#permalink]
Show Tags
21 Jun 2018, 00:16
hrishipatil72 wrote: Hi Bunuel,
"If the mean of set S does not exceed mean of any subset of set S''
Does it have to be true that Mean of S and Mean of any subset of S is equal? What if set S has negative numbers?
For Ex: S= {3,4,5,6,7} and subset of S is {3,4,5,6}. Here mean does not exceed but is lower that its subset.
In above example none of the three statement holds true? Could you please advise.
Thank you. The mean of {3, 4, 5, 6, 7} is 2.2. The mean of one of the subset of the above set, {3, 7}, is 2. So, your example is not valid. The stem says: "The mean of set \(S\) does not exceed mean of ANY subset of set \(S\)".
_________________



Intern
Joined: 05 Mar 2018
Posts: 29

Re M1623
[#permalink]
Show Tags
10 Aug 2018, 03:47
I don't agree with the explanation. Statement III. If median of set = mean of set eg. mean {0,1,2} = median {0,1,2} = 1 here, mean exceeds the subset of set which is {2}.
Only II should be the corret answer?



Math Expert
Joined: 02 Sep 2009
Posts: 58396

Re: M1623
[#permalink]
Show Tags
10 Aug 2018, 03:59
MittalMewada wrote: I don't agree with the explanation. Statement III. If median of set = mean of set eg. mean {0,1,2} = median {0,1,2} = 1 here, mean exceeds the subset of set which is {2}.
Only II should be the corret answer? I would not address your doubt. Instead I'd advice to read the whole thread. Your question is answered there many times.
_________________



Intern
Joined: 26 Jun 2018
Posts: 1

Re M1623
[#permalink]
Show Tags
16 Aug 2019, 07:42
I think this is a highquality question and I don't agree with the explanation.
Posted from my mobile device



Math Expert
Joined: 02 Sep 2009
Posts: 58396

Re: M1623
[#permalink]
Show Tags
16 Aug 2019, 07:46
Koushini wrote: I think this is a highquality question and I don't agree with the explanation.
Posted from my mobile device The solution is 100% correct. Please read the whole discussion. Hope it helps.
_________________







Go to page
Previous
1 2
[ 38 posts ]



