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# M16-29

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Math Expert
Joined: 02 Sep 2009
Posts: 47220

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16 Sep 2014, 00:59
13
00:00

Difficulty:

95% (hard)

Question Stats:

52% (01:51) correct 48% (02:48) wrong based on 85 sessions

Each month a retailer sells 100 identical items. On each item he makes a profit of $20 that constitutes 10% of the item's price to the retailer. If the retailer contemplates giving a 5% discount on the items he sells, what is the least number of items he will have to sell each month to justify the policy of the discount? A. 191 B. 213 C. 221 D. 223 E. 226 _________________ Math Expert Joined: 02 Sep 2009 Posts: 47220 Re M16-29 [#permalink] ### Show Tags 16 Sep 2014, 00:59 2 Official Solution: Each month a retailer sells 100 identical items. On each item he makes a profit of$20 that constitutes 10% of the item's price to the retailer. If the retailer contemplates giving a 5% discount on the items he sells, what is the least number of items he will have to sell each month to justify the policy of the discount?

A. 191
B. 213
C. 221
D. 223
E. 226

The current net monthly profit $$=20 * 100 =2000$$. The item's price to the retailer = $$\frac{20}{10}*100=200$$. The current selling price of one item $$=200 + \text{ (profit on each item) }=220$$.

The selling price of one item with the discount $$=220 (1 - 0.05) =200 -11 =209$$. The new profit on each item $$=209 -200 =9$$. The new net monthly profit $$= x *9$$ where $$x$$ is the number of items the retailer will sell after the discount is announced. The question is what must be $$x$$ so that the new net monthly profit would exceed the current net monthly profit. In other words, what is the least $$x$$ such that $$9x \gt 2000$$? $$x$$ must be larger than $$\frac{2000}{9} = 222.222..$$. Because $$x$$ has to be an integer, the least $$x$$ is 223.

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Joined: 14 Jul 2014
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14 Jan 2015, 06:10
1
what is the least number of items he will have to sell each month to justify the policy of the discount? - KEYWORDS !!

POLICY - Current Profit = 20 * 100 = $2000 has to be maintained !! As per solving stmnts, Profit = 10% CP = 1/10 CP = 1/11 SP { Profit =1/n * CP = 1/(n+1) * SP } .... Formula Hence Profit = 20, CP = 200 , SP = 220 Now, 5% discount on SP = 209. Hence Profit = 209 - 200 =$ 9

The least number of items he will have to sell each month to justify policy
9x > 2000 . x >222.22

or Backsolve
( 9 * What? will give atleast $2000) Ans - D Director Status: Verbal Forum Moderator Joined: 17 Apr 2013 Posts: 540 Location: India GMAT 1: 710 Q50 V36 GMAT 2: 750 Q51 V41 GMAT 3: 790 Q51 V49 GPA: 3.3 Re: M16-29 [#permalink] ### Show Tags 02 Jul 2015, 01:45 3 Bunuel wrote: Official Solution: Each month a retailer sells 100 identical items. On each item he makes a profit of$20 that constitutes 10% of the item's price to the retailer. If the retailer contemplates giving a 5% discount on the items he sells, what is the least number of items he will have to sell each month to justify the policy of the discount?

A. 191
B. 213
C. 221
D. 223
E. 226

The current net monthly profit $$=20 * 100 =2000$$. The item's price to the retailer = $$\frac{20}{10}*100=200$$. The current selling price of one item $$=200 + \text{ (profit on each item) }=220$$.

The selling price of one item with the discount $$=220 (1 - 0.05) =200 -11 =209$$. The new profit on each item $$=209 -200 =9$$. The new net monthly profit $$= x *9$$ where $$x$$ is the number of items the retailer will sell after the discount is announced. The question is what must be $$x$$ so that the new net monthly profit would exceed the current net monthly profit. In other words, what is the least $$x$$ such that $$9x \gt 2000$$? $$x$$ must be larger than $$\frac{2000}{9} = 222.222..$$. Because $$x$$ has to be an integer, the least $$x$$ is 223.

I belive language is slightly unclear -
$20 that constitutes 10% of the item's price to the retailer. items price refers to Cost Price or selling price, normally Gmat prep question doesn't have that kind of ambiguity. _________________ Like my post Send me a Kudos It is a Good manner. My Debrief: http://gmatclub.com/forum/how-to-score-750-and-750-i-moved-from-710-to-189016.html Senior Manager Joined: 31 Mar 2016 Posts: 400 Location: India Concentration: Operations, Finance GMAT 1: 670 Q48 V34 GPA: 3.8 WE: Operations (Commercial Banking) Re M16-29 [#permalink] ### Show Tags 20 Aug 2016, 04:44 I think this is a high-quality question and I agree with explanation. Intern Joined: 07 Feb 2010 Posts: 2 Re: M16-29 [#permalink] ### Show Tags 19 Oct 2016, 02:05 1 There are two problems with the wording of this question. Firstly the reference should be to cost and not to 'price to the retailer' which is unclear and confusing. Secondly, the question does not specify that the discount is only applied to some of the products sold. Again unclear and confusing. Intern Joined: 09 Sep 2015 Posts: 25 M16-29 [#permalink] ### Show Tags 29 Mar 2017, 21:17 honchos wrote: Bunuel wrote: Official Solution: Each month a retailer sells 100 identical items. On each item he makes a profit of$20 that constitutes 10% of the item's price to the retailer. If the retailer contemplates giving a 5% discount on the items he sells, what is the least number of items he will have to sell each month to justify the policy of the discount?

A. 191
B. 213
C. 221
D. 223
E. 226

The current net monthly profit $$=20 * 100 =2000$$. The item's price to the retailer = $$\frac{20}{10}*100=200$$. The current selling price of one item $$=200 + \text{ (profit on each item) }=220$$.

The selling price of one item with the discount $$=220 (1 - 0.05) =200 -11 =209$$. The new profit on each item $$=209 -200 =9$$. The new net monthly profit $$= x *9$$ where $$x$$ is the number of items the retailer will sell after the discount is announced. The question is what must be $$x$$ so that the new net monthly profit would exceed the current net monthly profit. In other words, what is the least $$x$$ such that $$9x \gt 2000$$? $$x$$ must be larger than $$\frac{2000}{9} = 222.222..$$. Because $$x$$ has to be an integer, the least $$x$$ is 223.

I belive language is slightly unclear -
$20 that constitutes 10% of the item's price to the retailer. items price refers to Cost Price or selling price, normally Gmat prep question doesn't have that kind of ambiguity. hi, Item's price always refers to selling price. above statement "$20 that constitutes 10% of the item's price to the retailer" can be written as -> 10% of Item Price=$20 =>$200.
Now total Selling Price(SP) = $200+$20(profit on each item) = $220 hope this helps. Intern Joined: 22 Jan 2017 Posts: 34 Re: M16-29 [#permalink] ### Show Tags 30 Sep 2017, 20:48 Yeah, the wording here is pretty ambiguous. Without going into anything else, there is no indication of what criteria are used to evaluate the suitability of the discount whatsoever. The question could very easily have been amended to ask, "what is the least number of items that the retailer must sell such that his net profit exceeds his current profit?" I think this is a good question, but that last line really need a bit more clarity. Intern Joined: 27 Apr 2011 Posts: 10 GMAT Date: 06-13-2017 Re: M16-29 [#permalink] ### Show Tags 04 Oct 2017, 10:19 Ambiguous Wording of the question.. please rectify ASAP. Manager Joined: 23 Jan 2017 Posts: 75 M16-29 [#permalink] ### Show Tags 13 Dec 2017, 13:30 Language not clear ... "justify the policy of the discount"? The question doesn't express what was the policy of the discount. I just made a guess that the question is trying to ask what is the least number of items he will have to sell so that his monthly profits doesn't decrease. This is not a 700 level question. It is just that the language is making it difficult to comprehend the question. Senior Manager Joined: 12 Feb 2015 Posts: 334 Re: M16-29 [#permalink] ### Show Tags 07 Jul 2018, 01:42 honchos wrote: Bunuel wrote: Official Solution: Each month a retailer sells 100 identical items. On each item he makes a profit of$20 that constitutes 10% of the item's price to the retailer. If the retailer contemplates giving a 5% discount on the items he sells, what is the least number of items he will have to sell each month to justify the policy of the discount?

A. 191
B. 213
C. 221
D. 223
E. 226

The current net monthly profit $$=20 * 100 =2000$$. The item's price to the retailer = $$\frac{20}{10}*100=200$$. The current selling price of one item $$=200 + \text{ (profit on each item) }=220$$.

The selling price of one item with the discount $$=220 (1 - 0.05) =200 -11 =209$$. The new profit on each item $$=209 -200 =9$$. The new net monthly profit $$= x *9$$ where $$x$$ is the number of items the retailer will sell after the discount is announced. The question is what must be $$x$$ so that the new net monthly profit would exceed the current net monthly profit. In other words, what is the least $$x$$ such that $$9x \gt 2000$$? $$x$$ must be larger than $$\frac{2000}{9} = 222.222..$$. Because $$x$$ has to be an integer, the least $$x$$ is 223.

I belive language is slightly unclear -
\$20 that constitutes 10% of the item's price to the retailer.

items price refers to Cost Price or selling price, normally Gmat prep question doesn't have that kind of ambiguity.

I agree the question per se is very easy but the ambiguity in wording leaves it open for interpretation & then its like you are gambling rather than solving GMAT quant.
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Re: M16-29 &nbs [#permalink] 07 Jul 2018, 01:42
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