nikita.nanda1810
Bunuel Can you help with explaining this with a number and what logically forces |a| = |b| for these equalities to be true?
And when is it okay to multiply equations.
Let a = 3, b = -3, c = 2, d = -2.
Then a/b = 3/(-3) = -1 and c/d = 2/(-2) = -1, so a/b = c/d.
Also a/d = 3/(-2) = -1.5 and b/c = (-3)/2 = -1.5, so a/d = b/c.
In this example, |a| = |b| because |3| = |-3|.
What logically forces |a| = |b| is:
From a/b = c/d you get ad = bc.
From a/d = b/c you get ac = bd.
Multiply them: (ad)(ac) = (bc)(bd) so a^2cd = b^2cd.
Since c and d are nonzero, cd is nonzero, so you can cancel cd and get a^2 = b^2, which means a = b or a = -b, hence |a| = |b|.
It is fine to multiply two equations when both equations are true at the same time.
Please review the discussion above for more.
Hope it helps.