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# M17-19

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Math Expert
Joined: 02 Sep 2009
Posts: 44586

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16 Sep 2014, 01:01
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15% (low)

Question Stats:

79% (00:39) correct 21% (00:42) wrong based on 202 sessions

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Is $$x \gt y$$ ?

(1) $$\frac{x + y}{x - y} = 1$$

(2) $$x \gt 0$$
[Reveal] Spoiler: OA

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Math Expert
Joined: 02 Sep 2009
Posts: 44586

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16 Sep 2014, 01:01
Official Solution:

Statements (1) and (2) combined are sufficient. From S1 it follows that $$x + y = x - y$$ or $$y = 0$$. Combining this information with $$x \gt 0$$ from S2, we conclude that $$x \gt y$$.

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Joined: 18 Mar 2015
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GMAT 1: 600 Q47 V26
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14 Aug 2016, 10:24
can someone explain me more ?
my logic
x+y=x-y
y = 1/2

from statement 2, x>0 means x can 1/2 , 1 , 2

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Joined: 02 Sep 2009
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15 Aug 2016, 03:42
r19 wrote:
can someone explain me more ?
my logic
x+y=x-y
y = 1/2

from statement 2, x>0 means x can 1/2 , 1 , 2

x+y=x-y
x cancels out: y = -y
2y = 0
y = 0.
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05 May 2017, 02:47
The answer must be option C.

Statement 1) This gives x+y=x-y ,i.e. y=0. Not sufficient
Statement 2) x>0 . This is clearly not sufficient.

Combine the two statements y=0 and x>o .ie, x>y.

Hence the answer is option C.
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Joined: 17 Mar 2017
Posts: 3
Location: United States
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05 May 2017, 12:43
I don't get it? What if I come up with y=0, and I put it in the equation given, I will find that x = 1; thus x>y. That means, I can solve the question without using x>0. Can someone answer me?
Math Expert
Joined: 02 Sep 2009
Posts: 44586

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05 May 2017, 12:51
2
KUDOS
Expert's post
linhmiu wrote:
I don't get it? What if I come up with y=0, and I put it in the equation given, I will find that x = 1; thus x>y. That means, I can solve the question without using x>0. Can someone answer me?

If you put y = 0 into (x + y)/(x - y) = 1 you'll get x/x = 1, which is true for any non-zero x, not only for x = 1. For example, try x = -1.

Hope it helps.
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10 Aug 2017, 04:22
I missed the case in which x= + 1 and -1 both....silly one...
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Joined: 09 Sep 2015
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17 Sep 2017, 04:44
Bunuel wrote:
r19 wrote:
can someone explain me more ?
my logic
x+y=x-y
y = 1/2

from statement 2, x>0 means x can 1/2 , 1 , 2

x+y=x-y
x cancels out: y = -y
2y = 0
y = 0.

Hi Bunuel

Cant we substitute y=0 back into the statement to find value of x ?

Thanks
Math Expert
Joined: 02 Sep 2009
Posts: 44586

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17 Sep 2017, 04:48
Bunuel wrote:
r19 wrote:
can someone explain me more ?
my logic
x+y=x-y
y = 1/2

from statement 2, x>0 means x can 1/2 , 1 , 2

x+y=x-y
x cancels out: y = -y
2y = 0
y = 0.

Hi Bunuel

Cant we substitute y=0 back into the statement to find value of x ?

Thanks

Check this: https://gmatclub.com/forum/m17-184125.html#p1847599
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GMAT 1: 570 Q40 V28
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10 Apr 2018, 00:13
As from a) x+y=x-y, y must be 0, as it doesn't make any difference in the equation.
from b) we get x>0, so the answer is C.
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Re: M17-19   [#permalink] 10 Apr 2018, 00:13
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# M17-19

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