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This question looks doubtful to me,
Lets see both the equations first, without going into further calculations

x=3(y+z)

y=z+9

This means y is greater than z and x is greater than both of other numbers. GMAT has some hidden rules about these type of questions. one of them is VOTE can not be negative and other is vote can not be in fraction.

Lets look at by putting simple numbers
If smallest number z is 1 then y=10 and x=33
by adding them we will get 44 minimum, or else Votes will go in fractions.

need expert's opinion

What if z = 0? It's possible isn't it? A candidate CAN receive 0 votes.
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Bunuel
This question looks doubtful to me,
Lets see both the equations first, without going into further calculations

x=3(y+z)

y=z+9

This means y is greater than z and x is greater than both of other numbers. GMAT has some hidden rules about these type of questions. one of them is VOTE can not be negative and other is vote can not be in fraction.

Lets look at by putting simple numbers
If smallest number z is 1 then y=10 and x=33
by adding them we will get 44 minimum, or else Votes will go in fractions.

need expert's opinion

What if z = 0? It's possible isn't it? A candidate CAN receive 0 votes.

That makes the solution even easier :-D Good point
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Bunuel
In a certain clu+ b election for chairman, each member voted for one of the three candidates. If candidate 1 received three times as many votes as the other two candidates combined, and candidate 2 received nine more votes than candidate 3, which of the following could be the number of members in the club?

A. 24
B. 30
C. 32
D. 36
E. 40
­I got 36 by different method but by similar logic pls tell if its right or luck. Candidates X,Y,Z. X=3(Y+Z), Y=9+z. Now X+Y+Z= 3(Y+Z)+Z+9+z=3Y+5C+9
Now at the end there is 9 so the total no. should be divisible by 9. Only 36 option remains
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Vikramaditya00

Bunuel
In a certain clu+ b election for chairman, each member voted for one of the three candidates. If candidate 1 received three times as many votes as the other two candidates combined, and candidate 2 received nine more votes than candidate 3, which of the following could be the number of members in the club?

A. 24
B. 30
C. 32
D. 36
E. 40
­I got 36 by different method but by similar logic pls tell if its right or luck. Candidates X,Y,Z. X=3(Y+Z), Y=9+z. Now X+Y+Z= 3(Y+Z)+Z+9+z=3Y+5C+9
Now at the end there is 9 so the total no. should be divisible by 9. Only 36 option remains
­Hi Vikramaditya,

Thats not how things work. 19 also contains 9 in the unit digits place is it divisible 9 ?

 
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I like the solution - it’s helpful. I like the solution - it’s helpful. I missed that a candidate could get zero votes.
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But question says each member give votes to one of three candidates then how can z be zero, please help me to understand
Bunuel


What if z = 0? It's possible isn't it? A candidate CAN receive 0 votes.
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But question says each member give votes to one of three candidates then how can z be zero, please help me to understand


“Each member voted for one of the three candidates” means every member cast exactly one vote, not that every candidate must receive at least one vote.

So z can be 0. In that case, candidate 3 receives 0 votes, candidate 2 receives 9 votes, and candidate 1 receives 3 * 9 = 27 votes, for a total of 36 votes.
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