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M18-32

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Bunuel
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M18-32 [#permalink] New post   16 Sep 2014, 01:04
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C
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94% (00:59) correct 6% (01:46) wrong based on 161 sessions
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If an executive received a 20% salary increase from 1995 to 1996 but then experienced a 25% decrease from 1996 to 1997, by what percentage was the executive's salary in 1997 lower than in 1995?

A. 5
B. 8
C. 10
D. 12
E. 15
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C
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Bunuel
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Re M18-32 [#permalink] New post   16 Sep 2014, 01:04
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Official Solution:

If an executive received a 20% salary increase from 1995 to 1996 but then experienced a 25% decrease from 1996 to 1997, by what percentage was the executive's salary in 1997 lower than in 1995?

A. 5
B. 8
C. 10
D. 12
E. 15


Let \(x\) represent the executive's salary in 1995. The salary in 1996 would then be \(1.2x\). By 1997, after a 25% decrease, the salary becomes \(1.2x*0.75 = 0.9x\). Therefore, in 1997, the executive's salary was \(\frac{x - 0.9x}{x}*100\% = 10\%\) lower than in 1995.


Answer: C
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89renegade
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Re: M18-32 [#permalink] New post   27 Jun 2016, 16:56
Bunuel wrote:
Official Solution:

If an executive's salary increased by 20% from 1995 to 1996 but decreased by 25% from 1996 to 1997, what percent lower was the executive's salary in 1997 than in 1995?

A. 5
B. 8
C. 10
D. 12
E. 15

Denote \(x\) as the executive's salary in 1995. Then the executive's salary in 1996 was \(1.2x\) while in 1997 it was \(1.2*0.75*x = 0.9x\). Thus, in 1997 the executive's salary was \(\frac{x - 0.9x}{x}*100\% = 10\%\) lower than in 1995.

Answer: C



Instead of x if I use a number for eg 10 then 1995 -->10, 1996--.1.2x10=12 and 1997 is 9 so when I do the next step to find percent lower (10-9)/9x100=11.11 I am not getting 12 exactly .Can you please explain where am I going wrong?
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Bunuel
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Re: M18-32 [#permalink] New post   28 Jun 2016, 05:34
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89renegade wrote:
Bunuel wrote:
Official Solution:

If an executive's salary increased by 20% from 1995 to 1996 but decreased by 25% from 1996 to 1997, what percent lower was the executive's salary in 1997 than in 1995?

A. 5
B. 8
C. 10
D. 12
E. 15

Denote \(x\) as the executive's salary in 1995. Then the executive's salary in 1996 was \(1.2x\) while in 1997 it was \(1.2*0.75*x = 0.9x\). Thus, in 1997 the executive's salary was \(\frac{x - 0.9x}{x}*100\% = 10\%\) lower than in 1995.

Answer: C



Instead of x if I use a number for eg 10 then 1995 -->10, 1996--.1.2x10=12 and 1997 is 9 so when I do the next step to find percent lower (10-9)/9x100=11.11 I am not getting 12 exactly .Can you please explain where am I going wrong?


1995 - 10
1996 - 12
1997 - 9

(10 - 9)/10 = 1/10.
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Bunuel
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Re: M18-32 [#permalink] New post   17 Oct 2023, 00:39
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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Re: M18-32 [#permalink]
17 Oct 2023, 00:39
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Bunuel
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