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While evaluating the second statement, I considered value of P = 1 , so Sqrt of 1 = 1 and 1 square is not prime, Using both Statement 1 and 2 eliminates the possiblity of P taking the value of 1.

While evaluating the second statement, I considered value of P = 1 , so Sqrt of 1 = 1 and 1 square is not prime, Using both Statement 1 and 2 eliminates the possiblity of P taking the value of 1.

Can you please explain ?

Regards,

It's not clear what you are trying to say there. From (2) it follows that p is an integer. The question asks whether p^2 is prime. If p is an integer, then p^2 cannot be a prime. Thus (2) is sufficient on its own (answer B) and we don not need to consider the statements together.
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1) p>1 means p=2,3,4 --- .. consider p=2 then p^2 is 2^2 is 4.. Not a prime.. it'll work for all the integers greater than 1 so 1st statement is sufficient right.

1) p>1 means p=2,3,4 --- .. consider p=2 then p^2 is 2^2 is 4.. Not a prime.. it'll work for all the integers greater than 1 so 1st statement is sufficient right.

1. \(p=2\) --> \(p^2=4\) or\(p=\sqrt{2}\)--> \(p=2\). Not Sufficient. 2. \(\sqrt{p}=Integer\). Hence\(p^2\) has 4 factors for sure (1,\(\sqrt{p}\),p and \(p^2\)). Hence its not prime Sufficient. Hence Its B. :)