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# M19-25

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Math Expert
Joined: 02 Sep 2009
Posts: 43810

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16 Sep 2014, 00:06
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Difficulty:

25% (medium)

Question Stats:

73% (01:19) correct 27% (01:21) wrong based on 143 sessions

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A shop sells candy bars individually or in packs of 10. If the shop charges less for purchasing a pack of 10 candy bars than for purchasing 10 candy bars individually, then how much does the shop charge for purchasing a pack of 10 candy bars?

(1) The charge for purchasing a pack of 10 candy bars is $2 more than the charge for purchasing the 8 candy bars. (2) The charge for purchasing a pack of 10 candy bars is 10 percent less than the charge for purchasing the 10 candy bars individually. [Reveal] Spoiler: OA _________________ Math Expert Joined: 02 Sep 2009 Posts: 43810 Re M19-25 [#permalink] ### Show Tags 16 Sep 2014, 00:06 Expert's post 1 This post was BOOKMARKED Official Solution: Say the price for purchasing a pack of 10 candy bars is $$x$$ and the price for purchasing the candy bar individually is $$y$$. (1) The charge for purchasing a pack of 10 candy bars is$2 more than the charge for purchasing the 8 candy bars. Given: $$x=8y+2$$. Two unknowns one equation. Not sufficient to calculate $$x$$.

(2) The charge for purchasing a pack of 10 candy bars is 10 percent less than the charge for purchasing the 10 candy bars individually. Given: $$x=0.9*10y$$. Two unknowns one equation. Not sufficient to calculate $$x$$.

(1)+(2) We have two distinct linear equations with two unknowns so we can solve for $$x$$ and $$y$$. Sufficient.

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Intern
Joined: 31 Mar 2016
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04 Sep 2017, 00:18
Hi there

Just wondering if the first stmt could be true by itself?

From the facts we understand that one pack of 10 is cheaper than 10 individual bars. I.e. X < 10Y

From first statement we have that X-8Y=2

If X is less than 10Y but must be greater than 8Y, could we say that it should be 9Y here. Or am I am I just assuming that it should be an integer..
Math Expert
Joined: 02 Sep 2009
Posts: 43810

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04 Sep 2017, 00:32
warmpied wrote:
Hi there

Just wondering if the first stmt could be true by itself?

From the facts we understand that one pack of 10 is cheaper than 10 individual bars. I.e. X < 10Y

From first statement we have that X-8Y=2

If X is less than 10Y but must be greater than 8Y, could we say that it should be 9Y here. Or am I am I just assuming that it should be an integer..

Yes, we are not told that x and y must be integers.
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Manager
Joined: 22 May 2017
Posts: 95
GMAT 1: 580 Q41 V29
GMAT 2: 580 Q43 V27

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20 Dec 2017, 19:07
Bunuel wrote:
warmpied wrote:
Hi there

Just wondering if the first stmt could be true by itself?

From the facts we understand that one pack of 10 is cheaper than 10 individual bars. I.e. X < 10Y

From first statement we have that X-8Y=2

If X is less than 10Y but must be greater than 8Y, could we say that it should be 9Y here. Or am I am I just assuming that it should be an integer..

Yes, we are not told that x and y must be integers.

Bunuel technically, how a candy bar can be integer.
I think answer should be A.
Math Expert
Joined: 02 Sep 2009
Posts: 43810

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20 Dec 2017, 19:25
Bunuel wrote:
warmpied wrote:
Hi there

Just wondering if the first stmt could be true by itself?

From the facts we understand that one pack of 10 is cheaper than 10 individual bars. I.e. X < 10Y

From first statement we have that X-8Y=2

If X is less than 10Y but must be greater than 8Y, could we say that it should be 9Y here. Or am I am I just assuming that it should be an integer..

Yes, we are not told that x and y must be integers.

Bunuel technically, how a candy bar can be integer.
I think answer should be A.

x = 8y + 2. Consider two cases:

x = 18 and y = 2 (notice x < 10y is satisfied);
x = 26 and y = 3 (notice x < 10y is satisfied).
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Re: M19-25   [#permalink] 20 Dec 2017, 19:25
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# M19-25

Moderators: chetan2u, Bunuel

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