lydennis8 wrote:
Bunuel,
how do you get from kx+b= (x - b) / k to x = b(k+1)/1−k2 ? the "1-k2" in the denominator i just cant figure out how you get that.
\(kx+b= \frac{(x - b)}{k}\)
Multiply by k: \(k^2x + bk = x - b\)
Rearrange: \(bk + b = x - k^2x\)
Factor out b and x: \(b(k + 1) = x(1 - k^2)\)
\(\frac{b(k + 1)}{(1 - k^2)} = x\).
Hope it's clear.
Goal: Q49, V41
+1 Kudos if you like my post pls!