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M19-32

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M19-32  [#permalink]

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New post 16 Sep 2014, 01:07
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A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

84% (01:04) correct 16% (00:57) wrong based on 159 sessions

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Re M19-32  [#permalink]

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New post 16 Sep 2014, 01:07
Official Solution:

Jane is 5 years younger than George. George is 2 years older than Alice. If the aggregate age of Jane, George, and Alice is 68 years, how old is Jane?

A. 20
B. 22
C. 23
D. 25
E. 28


Jane is 5 years younger than George: \(J=G-5\);

George is 2 years older than Alice: \(A=G-2\);

The aggregate age of Jane, George, and Alice is 68 years: \(J+G+A=68\). Substitute: \((G-5)+G+(G-2)=68\), which gives \(G=25\).

Since \(J=G-5\) then \(J=25-5=20\).


Answer: A
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Re: M19-32  [#permalink]

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New post 05 Sep 2017, 23:36
Bunuel wrote:
Jane is 5 years younger than George. George is 2 years older than Alice. If the aggregate age of Jane, George, and Alice is 68 years, how old is Jane?

A. 20
B. 22
C. 23
D. 25
E. 28






J = G-5
G = 2+A
A+G+J = 68
J=?

(G-2)+G+(G-5)=68
3G=75
G=25
J=25-5=20
Ans is A
GMAT Club Bot
Re: M19-32   [#permalink] 05 Sep 2017, 23:36
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M19-32

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