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# M19-32

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Math Expert
Joined: 02 Sep 2009
Posts: 54376

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16 Sep 2014, 01:07
00:00

Difficulty:

5% (low)

Question Stats:

84% (01:04) correct 16% (00:57) wrong based on 159 sessions

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Jane is 5 years younger than George. George is 2 years older than Alice. If the aggregate age of Jane, George, and Alice is 68 years, how old is Jane?

A. 20
B. 22
C. 23
D. 25
E. 28

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Math Expert
Joined: 02 Sep 2009
Posts: 54376

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16 Sep 2014, 01:07
Official Solution:

Jane is 5 years younger than George. George is 2 years older than Alice. If the aggregate age of Jane, George, and Alice is 68 years, how old is Jane?

A. 20
B. 22
C. 23
D. 25
E. 28

Jane is 5 years younger than George: $$J=G-5$$;

George is 2 years older than Alice: $$A=G-2$$;

The aggregate age of Jane, George, and Alice is 68 years: $$J+G+A=68$$. Substitute: $$(G-5)+G+(G-2)=68$$, which gives $$G=25$$.

Since $$J=G-5$$ then $$J=25-5=20$$.

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Joined: 14 Mar 2015
Posts: 16
Location: India
Concentration: General Management, Strategy
Schools: ISB '18, IIMA , IIMB
GPA: 3.53
WE: Engineering (Other)

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05 Sep 2017, 23:36
Bunuel wrote:
Jane is 5 years younger than George. George is 2 years older than Alice. If the aggregate age of Jane, George, and Alice is 68 years, how old is Jane?

A. 20
B. 22
C. 23
D. 25
E. 28

J = G-5
G = 2+A
A+G+J = 68
J=?

(G-2)+G+(G-5)=68
3G=75
G=25
J=25-5=20
Ans is A
Re: M19-32   [#permalink] 05 Sep 2017, 23:36
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# M19-32

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