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M20-37

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M20-37 [#permalink]

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New post 16 Sep 2014, 01:09
1
2
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

58% (00:52) correct 42% (00:50) wrong based on 146 sessions

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Re M20-37 [#permalink]

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New post 16 Sep 2014, 01:09
Official Solution:


Statement (1) by itself is insufficient. Consider \(A \gt B \gt 0\) (the answer is "yes") and \(x = 1000\), \(y = 1\), \(A = -1\), \(B = -2\) (the answer is "no").

Statement (2) by itself is insufficient. The answer is "yes" if \(A \gt B \gt 0\) but the answer is "no" if \(A \lt 0\).

Statements (1) and (2) combined are sufficient. It follows from S1 and S2 that \(A \gt B \gt 0\).


Answer: C
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Re: M20-37 [#permalink]

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New post 04 Nov 2014, 09:21
Is there a more algebraic approach we can take here?

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Re: M20-37 [#permalink]

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New post 02 Nov 2017, 05:41
+1 for option C. Both x and y are positive. To ascertain if Ax>By, we need to know the relationship between A and B. Besides , we need to know whether A and B are positive or not. This is important as inequality changes sign with the sign of the number we multiply it with.

Statement 1 : NS
Statement 2 : NS

Both together ---> Sufficient.

Hence option C.
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Re: M20-37   [#permalink] 02 Nov 2017, 05:41
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