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# M20-37

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Math Expert
Joined: 02 Sep 2009
Posts: 47109
M20-37 [#permalink]

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16 Sep 2014, 01:09
1
2
00:00

Difficulty:

45% (medium)

Question Stats:

58% (00:52) correct 42% (00:50) wrong based on 146 sessions

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If $$x \gt y \gt 0$$, is $$Ax \gt By$$ ?

(1) $$A \gt B$$

(2) $$B \gt 0$$

_________________
Math Expert
Joined: 02 Sep 2009
Posts: 47109
Re M20-37 [#permalink]

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16 Sep 2014, 01:09
Official Solution:

Statement (1) by itself is insufficient. Consider $$A \gt B \gt 0$$ (the answer is "yes") and $$x = 1000$$, $$y = 1$$, $$A = -1$$, $$B = -2$$ (the answer is "no").

Statement (2) by itself is insufficient. The answer is "yes" if $$A \gt B \gt 0$$ but the answer is "no" if $$A \lt 0$$.

Statements (1) and (2) combined are sufficient. It follows from S1 and S2 that $$A \gt B \gt 0$$.

Answer: C
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Manager
Joined: 08 Feb 2014
Posts: 205
Location: United States
Concentration: Finance
GMAT 1: 650 Q39 V41
WE: Analyst (Commercial Banking)
Re: M20-37 [#permalink]

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04 Nov 2014, 09:21
Is there a more algebraic approach we can take here?

Thanks
Director
Joined: 08 Jun 2015
Posts: 517
Location: India
GMAT 1: 640 Q48 V29
GMAT 2: 700 Q48 V38
Re: M20-37 [#permalink]

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02 Nov 2017, 05:41
+1 for option C. Both x and y are positive. To ascertain if Ax>By, we need to know the relationship between A and B. Besides , we need to know whether A and B are positive or not. This is important as inequality changes sign with the sign of the number we multiply it with.

Statement 1 : NS
Statement 2 : NS

Both together ---> Sufficient.

Hence option C.
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Re: M20-37   [#permalink] 02 Nov 2017, 05:41
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# M20-37

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